GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In this diagram, the circle is inscribed in a square
[#permalink]
15 Nov 2022, 01:01
15 Nov 2022, 01:01
1
Expert Reply
00:00
Question Stats:
88% (00:58) correct
11% (01:12) wrong based on 9 sessions
Hide Show timer Statistics
In this diagram, the circle is inscribed in a square
GRE circle inside a square.jpg [ 11.82 KiB | Viewed 2074 times ]
ABCD is a square. The circle has a radius r
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Attachment:
GRE circle inside a square.jpg [ 11.82 KiB | Viewed 2074 times ]
ABCD is a square. The circle has a radius r
Quantity A |
Quantity B |
Length of diagonal AC |
\(\frac{5r}{2}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: In this diagram, the circle is inscribed in a square
[#permalink]
21 Nov 2022, 08:11
21 Nov 2022, 08:11
Solution please...
In this diagram, the circle is inscribed in a square
[#permalink]
21 Nov 2022, 08:49
21 Nov 2022, 08:49
Expert Reply
Attachment:
GRE circle inside a square.jpg [ 14.13 KiB | Viewed 1816 times ]
The diagonal ACV is actually the diameter of the circle. From this we can also conclude that the two side of the square are twice the radius of the circle. As such, 2r
Now we can setup all the necessary to find D
(2r)^2+(2r)^2=d^2
Solve and we do have \(d=\sqrt{8} r\)
Comparing \(\sqrt{8} r\) and \(\frac{5r}{2}\) clearly A > B
A is the answer
