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If the x-coordinates of the two x-intercepts of a parabola are 3 an
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08 Dec 2022, 03:16
08 Dec 2022, 03:16
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Question Stats:
65% (01:22) correct
34% (01:16) wrong based on 23 sessions
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If the x-coordinates of the two x-intercepts of a parabola are \(3 − \sqrt{2}\) and \(5 + \sqrt{2}\), then what is the distance between them?
\(2 − 2 \sqrt{2} \)
\(2 + 2 \sqrt{2} \)
\(8 + 2 \sqrt{2}\)
2
8
\(2 − 2 \sqrt{2} \)
\(2 + 2 \sqrt{2} \)
\(8 + 2 \sqrt{2}\)
2
8
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: If the x-coordinates of the two x-intercepts of a parabola are 3 an
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08 Dec 2022, 23:25
08 Dec 2022, 23:25
1
Expert Reply
The question basically asks what is the distance between \(3 – √2\) and \(5 + √2\)
\(=> (5 + √2) - ( 3 – √2)
= 5 + √2 - 3 + √2
= 2 + 2√2\)
Answer: B
\(=> (5 + √2) - ( 3 – √2)
= 5 + √2 - 3 + √2
= 2 + 2√2\)
Answer: B
Re: If the x-coordinates of the two x-intercepts of a parabola are 3 an
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11 Dec 2022, 04:00
11 Dec 2022, 04:00
1
Expert Reply
OE
You don’t need to use the distance formula, because the distance between the points \((3 − \sqrt{2}, 0) and (5 + \sqrt{2}, 0)\) can be measured horizontally. Distance is positive, so subtract the smaller x-coordinate from the larger: \((5 + \sqrt{2}) − (3 − \sqrt{2} ) = 2 + 2 \sqrt{2}\); the answer is choice (B).
You don’t need to use the distance formula, because the distance between the points \((3 − \sqrt{2}, 0) and (5 + \sqrt{2}, 0)\) can be measured horizontally. Distance is positive, so subtract the smaller x-coordinate from the larger: \((5 + \sqrt{2}) − (3 − \sqrt{2} ) = 2 + 2 \sqrt{2}\); the answer is choice (B).
