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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
If xy > 0 and yz < 0, which of the following must be negative?
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12 Dec 2022, 05:51
12 Dec 2022, 05:51
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Question Stats:
49% (01:24) correct
49% (01:18) wrong based on 14 sessions
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If xy > 0 and yz < 0, which of the following must be negative?
(A) \(xyz\)
(B) \(x*y*z^2\)
(C) \(x*y^2*z\)
(D) \(x*y^2*z^2\)
(E) \(x^2*y^2*z^2\)
(A) \(xyz\)
(B) \(x*y*z^2\)
(C) \(x*y^2*z\)
(D) \(x*y^2*z^2\)
(E) \(x^2*y^2*z^2\)
Re: If xy > 0 and yz < 0, which of the following must be negative?
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14 Dec 2022, 05:15
14 Dec 2022, 05:15
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SOLUTION
If xy > 0 and yz < 0, which of the following must be negative?
(A) \(xyz\)
(B) \(x*y*z^2\)
(C) \(x*y^2*z\)
(D) \(x*y^2*z^2\)
(E) \(x^2*y^2*z^2\)
Notice that option C is \(x(y^2)z = (xy)(yz) = positive*negative = negative\).
Answer: C.
If xy > 0 and yz < 0, which of the following must be negative?
(A) \(xyz\)
(B) \(x*y*z^2\)
(C) \(x*y^2*z\)
(D) \(x*y^2*z^2\)
(E) \(x^2*y^2*z^2\)
Notice that option C is \(x(y^2)z = (xy)(yz) = positive*negative = negative\).
Answer: C.
Re: If xy > 0 and yz < 0, which of the following must be negative?
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12 Apr 2024, 08:45
12 Apr 2024, 08:45
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
