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Suppose that x and y are integers and that 0 < x < y < 10. The tenths
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19 Dec 2022, 09:43
19 Dec 2022, 09:43
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Question Stats:
88% (01:57) correct
11% (01:54) wrong based on 17 sessions
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Suppose that x and y are integers and that 0 < x < y < 10. The tenths digit of the decimal representation of x/16 is 5. What is the hundredths digit of the result of 17/y ?
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8
Re: Suppose that x and y are integers and that 0 < x < y < 10. The tenths
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29 Jan 2023, 12:05
29 Jan 2023, 12:05
Expert Reply
OE
Since the tenths digit of the decimal version of x/16=5 , x must have a value of at least half of 16. That is, x >= 8. Since y > x and y < 10, and both must be integers, x 17 9 must equal exactly 8 and y must equal exactly 9. Thus 17/y=17/9=1 8/9=1.888.
the answer is 8
Since the tenths digit of the decimal version of x/16=5 , x must have a value of at least half of 16. That is, x >= 8. Since y > x and y < 10, and both must be integers, x 17 9 must equal exactly 8 and y must equal exactly 9. Thus 17/y=17/9=1 8/9=1.888.
the answer is 8
Suppose that x and y are integers and that 0 < x < y < 10. The tenths
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24 Jan 2024, 01:22
24 Jan 2024, 01:22
1
If the tenths digit of the decimal representation of \(\frac{x}{16}\) is \(5\), then it means that \(\frac{x}{16} = 0.5 = \frac{1}{2} \text{ or
} x=8\)
Since \(y>x\), and \(y<10\), \(y=9\)
\(\text{ So, } \frac{17}{y} = \frac{17}{9} = 1.8888....\)
The hundredth digit of \(1.8888....\) is \(8\)
The answer is \(8\).
} x=8\)
Since \(y>x\), and \(y<10\), \(y=9\)
\(\text{ So, } \frac{17}{y} = \frac{17}{9} = 1.8888....\)
The hundredth digit of \(1.8888....\) is \(8\)
The answer is \(8\).
