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Joined: 20 Feb 2017
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Re: Two water pumps, working simultaneously at their respective constant
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24 Dec 2022, 02:21
Say the rate of the faster pump is x pool/hour, then the rate of the slower pump would be x/1.5=2x/3 pool/hour.
Since, the combined rate is 1/4 pool/hour, then we have that x+2x/3=1/4 --> x=3/20 pool hour.
The time is reciprocal of the rate, therefore it would take 20/3 hours the faster pump to fill the pool working alone.
Answer: E