GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the coordinate plane, for which of the following values of x would
[#permalink]
23 Dec 2022, 11:08
23 Dec 2022, 11:08
Expert Reply
1
Bookmarks
00:00
Question Stats:
70% (01:24) correct
29% (01:04) wrong based on 24 sessions
Hide Show timer Statistics
In the coordinate plane, for which of the following values of x would the graph of the equation \(y = x^3 - x^2 - 6x\) touch the x axis?
(A) 2
(B) -3
(C) -2
(D) 1
(E) 6
(A) 2
(B) -3
(C) -2
(D) 1
(E) 6
Re: In the coordinate plane, for which of the following values of x would
[#permalink]
26 Dec 2022, 05:00
26 Dec 2022, 05:00
Expert Reply
OE
In the coordinate plane, a line crosses the x-axis at values of x that return a y value of o. These points are known as the “roots” of the equation. To find the roots of the equation y = x^3 - x^2 - 6x, set y = 0 and factor the right side of the equation as follows:
0 = x^3-x^2-6 x
0 = x(x^2 - x - 6)
0 = x(x + 2) (x - 3)
Hence, y = 0 when x = 0, - 2, or 3. Only choice (C) matches one of these roots.
In the coordinate plane, a line crosses the x-axis at values of x that return a y value of o. These points are known as the “roots” of the equation. To find the roots of the equation y = x^3 - x^2 - 6x, set y = 0 and factor the right side of the equation as follows:
0 = x^3-x^2-6 x
0 = x(x^2 - x - 6)
0 = x(x + 2) (x - 3)
Hence, y = 0 when x = 0, - 2, or 3. Only choice (C) matches one of these roots.
Re: In the coordinate plane, for which of the following values of x would
[#permalink]
23 Nov 2024, 13:10
23 Nov 2024, 13:10
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
