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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Two water pumps, working simultaneously at their respective constant
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22 Dec 2022, 06:54
22 Dec 2022, 06:54
Expert Reply
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Question Stats:
75% (02:16) correct
25% (02:26) wrong based on 12 sessions
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Two water pumps, working simultaneously at their respective constant rates, took exactly four hours to fill a certain swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at it's constant rate?
A. 5
B. 16/3
C. 11/2
D. 6
E. 20/3
A. 5
B. 16/3
C. 11/2
D. 6
E. 20/3
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: Two water pumps, working simultaneously at their respective constant
[#permalink]
24 Dec 2022, 02:21
24 Dec 2022, 02:21
1
Expert Reply
Say the rate of the faster pump is x pool/hour, then the rate of the slower pump would be x/1.5=2x/3 pool/hour.
Since, the combined rate is 1/4 pool/hour, then we have that x+2x/3=1/4 --> x=3/20 pool hour.
The time is reciprocal of the rate, therefore it would take 20/3 hours the faster pump to fill the pool working alone.
Answer: E
Since, the combined rate is 1/4 pool/hour, then we have that x+2x/3=1/4 --> x=3/20 pool hour.
The time is reciprocal of the rate, therefore it would take 20/3 hours the faster pump to fill the pool working alone.
Answer: E
Re: Two water pumps, working simultaneously at their respective constant
[#permalink]
21 Mar 2025, 15:28
21 Mar 2025, 15:28
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