Carcass wrote:
Suppose that \(|x| < |y + 2| < |z|\). Suppose further that \(y > 0\) and that \(xz > 0\). Which of the following could be true ?
Indicate
all statements that apply
❑ \(0 < y < x < z\)
❑ \(0 < x < y < z\)
❑ \(x < z < 0 < y\)
❑ \(0 < y + 1.5 < x < z\)
❑ \(z < x < 0 < y\)
Given y > 0 and xz > 0)
Therefore : y must be positive,
Either x and z are both positive or they are both negative
If x and z are positive,
then y > x or y < x
Let us take two possibilities such as:
1. x = 1, y = 3, z = 6,
2. y = 2, x = 3, z = 6.
Then we can see that Option A and Option B are true For option C,
It cannot be true because If x and z are both negative, then x must be greater than z, since |z| > |x|.Option D
It can be true if we consider fraction let say, y = 1, x = 2.5, and z = 4. (As nothing is mentioned for the quantities to be integer, it can be fraction as well)
Option E
Similarly if x and z are both negative,
x = -1, y = 2, and z = -4 such that |z| > |x|, y > 0
so z < x