Last visit was: 26 Dec 2024, 23:41 It is currently 26 Dec 2024, 23:41
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

Jan and Marko are competing in an o?-road race. Jan complete

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30513
Own Kudos [?]: 36872 [6]
Given Kudos: 26109
Send PM
Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   27 Jan 2020, 03:26
Expert Reply
6
Bookmarks
00:00

Question Stats:

65% (02:38) correct 34% (02:39) wrong based on 186 sessions

Hide Show timer Statistics

Jan and Marko are competing in an off-road race. Jan completes 3/4 of the race in 2 hours. Marko completes 2/3 of the race in 5/8 of the time it takes Jan to complete 9/10 of the race.


Quantity A
Quantity B
Jan’s rate
Marko’s rate


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
ShowHide Answer
Official Answer
B
avatar
Nala16
Intern
Intern
Joined: 27 Jan 2020
Posts: 31
Own Kudos [?]: 36 [4]
Given Kudos: 0
Send PM
Re: Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   03 Feb 2020, 11:08
2
2
Bookmarks
Jans rate: 3/8 of the race in 1 hour

time it takes Jan to complete 9/10 of the race:
3/8 * t = 9/10 = 12/5 hours

Marko completes 2/3 of the race in 5/8 of the time it takes Jan to complete 9/10 (12/5 hours)

2/3 race = 5/8 * 12/5 hours= 12/8 hours= 3/2 hours

--> Marko completes 4/9 of the race in 1 hour --> higher rate than Jan --> B
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12238 [3]
Given Kudos: 136
Send PM

Top Member of the Month
Re: Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   04 Feb 2020, 08:08
2
1
Bookmarks
Carcass wrote:
Jan and Marko are competing in an off-road race. Jan completes 3/4 of the race in 2 hours. Marko completes 2/3 of the race in 5/8 of the time it takes Jan to complete 9/10 of the race.


Quantity A
Quantity B
Jan’s rate
Marko’s rate


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


Let d = the TOTAL distance of the race

Jan completes 3/4 of the race in 2 hours
Distance traveled = (3/4)(d) = 3d/4

Speed = distance/time
= (3d/4)/2
= 3d/8
So, Jan's speed = 3d/8

Marko completes 2/3 of the race in 5/8 of the time it takes Jan to complete 9/10 of the race
We already know that Jan's speed = 3d/8
9/10 of the race distance = 9d/10

Time it takes Jan to complete 9/10 of the race = distance/speed = (9d/10)/(3d/8) = (9d/10)(8/3d) = 72d/30d = 72/30 = 12/5 (hours)
5/8 of 12/5 = (5/8)(12/5) = 60/40 = 3/2
So, it takes Marko 3/2 hours to complete 2/3 of the race

2/3 of the race distance = 2d/3
Speed = distance/time
= (2d/3)/(3/2)
= (2d/3)(2/3)
= 4d/9
So, Marko's speed = 4d/9

We get:
QUANTITY A: 3d/8
QUANTITY B: 4d/9

Multiply both quantities by 72 to get:
QUANTITY A: 27d
QUANTITY B: 32d

Answer: B

Cheers,
Brent
avatar
Roccoporco555
Manager
Manager
Joined: 02 Feb 2020
Posts: 52
Own Kudos [?]: 62 [3]
Given Kudos: 0
Send PM
Re: Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   05 Feb 2020, 08:28
2
1
Bookmarks
Carcass wrote:
Jan and Marko are competing in an off-road race. Jan completes 3/4 of the race in 2 hours. Marko completes 2/3 of the race in 5/8 of the time it takes Jan to complete 9/10 of the race.


Quantity A
Quantity B
Jan’s rate
Marko’s rate


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


Let's assume that the race is 200 miles.

Time*Rate = Work

For Jan the equation is: 2*Rj = 150 (3/4 of 100)

Rj = 75

For Marko the equation is 5/8*2Rm = 180 (9/10 of 200)

Rm = 180/(10/8) = 18*8 = 144


Marko's rate is greater.
User avatar
D
KarunMendiratta
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 3273 [1]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   07 Mar 2021, 23:20
1
Carcass wrote:
Jan and Marko are competing in an off-road race. Jan completes 3/4 of the race in 2 hours. Marko completes 2/3 of the race in 5/8 of the time it takes Jan to complete 9/10 of the race.


Quantity A
Quantity B
Jan’s rate
Marko’s rate


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


Here Rate means Speed and Rate = \(\frac{Work}{Time}\)

Rate of Jan = \(\frac{0.75}{2} = 0.375\)

Time take by Jan to complete \(\frac{9}{10}\) distance = \((\frac{0.9}{0.375}) = 2.4\)

Now,
Rate of Marko \(= \frac{0.66}{0.625 of time taken by Jan to cover 0.9 distance}\)

\(\frac{0.66}{{(0.625)(2.4)}}\)

\(\frac{0.66}{1.5} = 0.444\)

Col. A: \(0.375\)
Col. B: \(0.444\)

Col. A < Col. B

Hence, option B
User avatar
B
BrDickinson
Manager
Manager
Joined: 03 Aug 2022
Posts: 54
Own Kudos [?]: 32 [0]
Given Kudos: 69
Send PM
Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   14 Aug 2022, 19:32
Sorry for those who love fractions (not my case).
Maybe integers (with some concession for decimals) can help...

Using the denominators (4*3*8*10). Say the race is 960km long.
Jan completes 3/4 of it (720km) in 2 hours, which is a rate of 340km/h.
Marko completes 2/3 of the race (640km) in 5/8 of the time it takes Jan to complete 9/10:
9/10 of the race is 864km/340 = 2.5 hours (rounding).
5/8 of this time is 1.6 (rounding).
640/1.59 is 408km/h

So Mark is faster :)
avatar
B
infopro
Intern
Intern
Joined: 17 Sep 2022
Posts: 16
Own Kudos [?]: 14 [2]
Given Kudos: 14
Send PM
Re: Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   24 Jan 2023, 02:36
2
I think the answer should be D because the question does not state that Jan and Marko are competing at a constant rate. We will have to assume that Jan will complete 9/10th of the race at the same rate as he completed 3/4th of the race, which may not be true. (Perhaps Jan stops for a nap after completing 3/4th of his race, lol!)
avatar
B
bauer14054
Intern
Intern
Joined: 06 Jun 2024
Posts: 1
Own Kudos [?]: 0 [0]
Given Kudos: 37
Send PM
Re: Jan and Marko are competing in an o?-road race. Jan complete [#permalink] New post   17 Jun 2024, 18:40
I think the question needs to specify that they are going at their respective constant rates. Otherwise, it should be D.
Prep Club for GRE Bot
gmatclubot
Re: Jan and Marko are competing in an o?-road race. Jan complete [#permalink]
17 Jun 2024, 18:40
Moderators:
adewale223
GRE Instructor
88 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1115 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact