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Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
If there are 320 workers then managers = 48 and directors = 9 Total = 377

Why not 48 mangers ? Is the question asking least number of managers possible
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Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
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In order to solve this multi-part Ratio problem, you must first establish a common term. As given, the number of managers appears as 3 in one ratio and as 5 in the other. The least common multiple of 3 and 5 is 15. Thus, by multiplying the first ratio by 3 and the second ratio by 3, you can make the number of managers the same, enabling you to combine the two ratios into one:

W : M = 20 : 3 = 100 : 15 and M : D = 5 : 1 = 15 : 3, so that W: M : D = 100 : 15 : 3

So, for every 3 directors, there will be 15 managers and 100 workers. Thus, a “unit” of employees is 3 + 15 + 100 = 118. From this, you see that the total number of em­ployees will need to be some integer multiple of 118. The only such number be­ tween 300 and 400 is 3 x 118, which is 334. Thus, the number of managers will be given by the same multiplier: 3x15 = 45.
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Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
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Carcass wrote:
OE

In order to solve this multi-part Ratio problem, you must first establish a common term. As given, the number of managers appears as 3 in one ratio and as 5 in the other. The least common multiple of 3 and 5 is 15. Thus, by multiplying the first ratio by 3 and the second ratio by 3, you can make the number of managers the same, enabling you to combine the two ratios into one:

W : M = 20 : 3 = 100 : 15 and M : D = 5 : 1 = 15 : 3, so that W: M : D = 100 : 15 : 3

So, for every 3 directors, there will be 15 managers and 100 workers. Thus, a “unit” of employees is 3 + 15 + 100 = 118. From this, you see that the total number of em­ployees will need to be some integer multiple of 118. The only such number be­ tween 300 and 400 is 3 x 118, which is 334. Thus, the number of managers will be given by the same multiplier: 3x15 = 45.

Thank you I got it. I was confused actually

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Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
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Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
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