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In any square, the relationship between the area A and the perimeter P

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In any square, the relationship between the area A and the perimeter P [#permalink] New post   05 Jan 2023, 00:12
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In any square, the relationship between the area A and the perimeter P is A=nP2, where n is a constant. What is the value of n2?


A. 1/4

B. 1/8

C. 1/32

D. 1/64

E. 1/256
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In any square, the relationship between the area A and the perimeter P [#permalink] New post   30 Jan 2023, 10:55
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The area of a square is given by the formula A = s^2, where s is the length of the square's side. The perimeter is given by P = 4s. Plugging these values into the equation given in the question, you can solve for n

s^2=n * (4s)^2

s^2=16s^2n

n=s^2/16s^2=1/16

n^2=(1/16)^2=1/256
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Re: In any square, the relationship between the area A and the perimeter P [#permalink] New post   27 Dec 2023, 20:17
If it helps to have something more concrete, you could just make up a square and plug those values in. For example, use square with length 1, and see where that gets you.
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Re: In any square, the relationship between the area A and the perimeter P [#permalink]
27 Dec 2023, 20:17
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