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Five consecutive even integers have a sum

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rajlal
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Five consecutive even integers have a sum [#permalink] New post   Updated on: 05 Sep 2018, 23:54
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Five consecutive even integers have a sum of −20.

Quantity A
Quantity B
The greatest of the five even
integers
0



A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
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C

Originally posted by rajlal on 05 Sep 2018, 14:57.
Last edited by Carcass on 05 Sep 2018, 23:54, edited 1 time in total.
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Re: Five consecutive even integers have a sum [#permalink] New post   05 Sep 2018, 23:55
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Hi rajal,

please format the question as you can see. Doing so is easy . Here is explained how to do https://gre.myprepclub.com/forum/qq-how-to ... -2357.html

Also, the title of the topic should be the first sentence of the question itself.

Thank you for your cooperation.

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Re: Five consecutive even integers have a sum [#permalink] New post   06 Sep 2018, 01:46
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5 consecutive even integers: 2n+(2n+2)+(2n+4)+(2n+6)+(2n+8)=-20 => 10n+20=-20 => n=-4 plug into the greatest of the 5, i.e. 2(-4)+8=0
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Re: Five consecutive even integers have a sum [#permalink] New post   06 Sep 2018, 12:29
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rajlal wrote:
Five consecutive even integers have a sum of −20.

Quantity A
Quantity B
The greatest of the five even
integers
0



A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


Even integers (...-4, -2, 0, 2, 4, 6, ...) increase by 2

Let x = the smallest even integer
So, x + 2 = the next integer
and x + 4 = the next integer
and x + 6 = the next integer
and x + 8 = the last (GREATEST) integer

We're told that the 5 integers add to -20
So, we can write: x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = -20
Simplify: 5x + 20 = -20
Subtract 20 from both sides to get: 5x = -40
Solve: x = -8

So, the 5 numbers are -8, -6, -4, -2, 0

The greatest is 0.
So, the quantities are EQUAL

Answer: C

Cheers,
Brent
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Five consecutive even integers have a sum [#permalink] New post   13 Mar 2021, 02:07
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rajlal wrote:
Five consecutive even integers have a sum of −20.

Quantity A
Quantity B
The greatest of the five even
integers
0



A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


\((x - 4) + (x - 2) + (x) + (x + 2) + (x + 4) = -20\)
\(5x = -20\)
\(x = -4\)

Col. A: \((x + 4) = 0\)
Col. B: \(0\)

Hence, option C
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eywilson
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Re: Five consecutive even integers have a sum [#permalink] New post   07 Feb 2023, 18:21
Why is it not D?

I also arrived at the above set, but then on this one, too: 4, 0, -4, -8, -12, in which case A > B.
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KarunMendiratta
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Re: Five consecutive even integers have a sum [#permalink] New post   10 Feb 2023, 08:10
eywilson wrote:
Why is it not D?

I also arrived at the above set, but then on this one, too: 4, 0, -4, -8, -12, in which case A > B.


But then, the numbers selected by you are not consecutive even integers. They form an AP but not consecutive.
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Re: Five consecutive even integers have a sum [#permalink]
10 Feb 2023, 08:10
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