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0 < a < 3 3 < b < 0 a and b are integers.
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27 Jan 2020, 03:30
27 Jan 2020, 03:30
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\(0 < a < 3\)
\(−3 < b < 0\)
a and b are integers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
\(−3 < b < 0\)
a and b are integers.
Quantity A |
Quantity B |
a+b |
a-b |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Re: 0 < a < 3 3 < b < 0 a and b are integers.
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27 Jan 2020, 06:31
27 Jan 2020, 06:31
3
Carcass wrote:
\(0 < a < 3\)
\(−3 < b < 0\)
a and b are integers.
\(−3 < b < 0\)
a and b are integers.
Quantity A |
Quantity B |
a+b |
a-b |
We can solve this question using matching operations
Given:
Quantity A: \(a+b\)
Quantity B: \(a-b\)
Subtract \(a\) from both quantities to get:
Quantity A: \(b\)
Quantity B: \(-b\)
Add \(b\) to both quantities to get:
Quantity A: \(2b\)
Quantity B: \(0\)
Divide both quantities by \(2\) to get:
Quantity A: \(b\)
Quantity B: \(0\)
From the given information, \(−3 < b < 0\), we're told that \(b\) is negative
As such, Quantity B must be greater.
Answer: B
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Re: 0 < a < 3 3 < b < 0 a and b are integers.
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29 Jan 2020, 06:39
29 Jan 2020, 06:39
1
1
0<a<3 -(1)
-3<b<0 -(2)
Add 1 & 2
-3< a + b < 3
Also, multiply -1 with (2)
Now, 0<-b<3 - (3)
Add 1 & 3
0<a-b<6
Hence, clearly answer is D
-3<b<0 -(2)
Add 1 & 2
-3< a + b < 3
Also, multiply -1 with (2)
Now, 0<-b<3 - (3)
Add 1 & 3
0<a-b<6
Hence, clearly answer is D
