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x>4
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16 Mar 2022, 02:00
16 Mar 2022, 02:00
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Question Stats:
41% (01:19) correct
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\(x>4\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(\frac{x+4}{x-4}\) |
\(x+10\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
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Given Kudos: 136
x>4
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16 Mar 2022, 05:06
16 Mar 2022, 05:06
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Carcass wrote:
\(x>4\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(\frac{x+4}{x-4}\) |
\(x+10\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Let's use matching operations to move all of the terms to one quantity (see the video lesson below )
Given:
Quantity A: \(\frac{x+4}{x-4}\)
Quantity B: \(x+10\)
Since \(x>4\), we know that \(x-4\) is POSITIVE, which means we can safely multiply both quantities by \(x-4\) to get:
Quantity A: \(x+4\)
Quantity B: \(x^2+6x-40\)
Subtract \(x\) from both quantities and subtract \(4\) from both quantities to get:
Quantity A: \(0\)
Quantity B: \(x^2+5x-44\)
At this point, it's easy to see that, if \(x = 0\), then Quantity A is greater.
And, if \(x = 100\), then Quantity B is greater.
Answer: D
RELATED VIDEO
Re: x>4
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25 May 2022, 22:22
25 May 2022, 22:22
2
After simplification:
Quantity A: 44
Quantity B: x(x+5)
For x=4.1, Quantity A is > Quantity B.
For x=5, quantity A is < Quantity B.
Ans D.
Quantity A: 44
Quantity B: x(x+5)
For x=4.1, Quantity A is > Quantity B.
For x=5, quantity A is < Quantity B.
Ans D.
