GreenlightTestPrep wrote:
Carcass wrote:
\(x>4\)
Quantity A |
Quantity B |
\(\frac{x+4}{x-4}\) |
\(x+10\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Let's use
matching operations to move all of the terms to one quantity (see the video lesson below )
Given:
Quantity A: \(\frac{x+4}{x-4}\)
Quantity B: \(x+10\)
Since \(x>4\), we know that \(x-4\) is POSITIVE, which means we can safely multiply both quantities by \(x-4\) to get:
Quantity A: \(x+4\)
Quantity B: \(x^2+6x-40\)
Subtract \(x\) from both quantities and subtract \(4\) from both quantities to get:
Quantity A: \(0\)
Quantity B: \(x^2+5x-44\)
At this point, it's easy to see that, if \(x = 0\), then Quantity A is greater.
And, if \(x = 100\), then Quantity B is greater.
Answer: D
RELATED VIDEO
I don't think the justification here is right to put x=0 since the question clearly says x>4. The other answer seems to be more accurate