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2^y or (1/2)^-y
[#permalink]
22 Feb 2023, 03:34
22 Feb 2023, 03:34
Expert Reply
00:00
Question Stats:
81% (00:38) correct
18% (01:23) wrong based on 16 sessions
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Quantity A |
Quantity B |
\( 2^y \) |
\([\frac{1}{2}]^{-y}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: 2^y or (1/2)^-y
[#permalink]
06 Mar 2023, 17:14
06 Mar 2023, 17:14
1
Quantity A
Quantity B
2y
2
�
[12]−y
[
1
2
]
−
�
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Lets take y = 4
So Quantity A = 2^4 = 2*2*2*2 = 16
Quantity B = (1/2) ^ - 4 = with the help of negative exponent rule this becomes, 2 ^ 4 = 2*2*2*2 = 16
Quantity A = Quantity B
So the answer is both quantity are equal i.e. C
Quantity B
2y
2
�
[12]−y
[
1
2
]
−
�
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Lets take y = 4
So Quantity A = 2^4 = 2*2*2*2 = 16
Quantity B = (1/2) ^ - 4 = with the help of negative exponent rule this becomes, 2 ^ 4 = 2*2*2*2 = 16
Quantity A = Quantity B
So the answer is both quantity are equal i.e. C
gmatclubot
Re: 2^y or (1/2)^-y [#permalink]
06 Mar 2023, 17:14
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