Love this kind of questions wher you work conceptually and also by estimation. The process is pretty fast to solve it

1) Take the square root of the stem. so we do have \(6 <\sqrt{ x} < 7\)

2) \(\sqrt{ x}\) is a number ranging from 6.1 to 6.9

Now

in QA we do have \(2^{\sqrt{ x}}\) and suppose that we have in the quantity a above 6

\(2^6 =64\)

QB 64 as well

But taking the \((2^{\sqrt{ x}})^2\) \(= 4^{6.1}\)

A > B