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The number of multiples of 7 between 50 and 100, inclusive
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22 Feb 2023, 07:07
22 Feb 2023, 07:07
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Question Stats:
74% (01:25) correct
24% (02:14) wrong based on 28 sessions
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Quantity A |
Quantity B |
The number of multiples of 7 between 50 and 100, inclusive |
The number of multiples of 9 between 30 and 90, inclusive |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: The number of multiples of 7 between 50 and 100, inclusive
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18 Mar 2023, 04:31
18 Mar 2023, 04:31
Expert Reply
OE
Both quantities can be solved straightforwardly with the equations. The first multiple of 7 between 50 and 100 is 56, and the last is 98. Thus: 98 − 56 = 42; ; 42/7=6 and 6 + 1 = 7. Another way to think about it is that 56 is the 8th multiple of 7, and 98 is the 14th multiple of 7. Now use the counting principle:
14 − 8 = 6 + 1 = 7
There are 7 multiples of 7 between 50 and 100. Similarly, the first multiple of 9 between 30 and 90 is 36, and the last is 90: 90 − 36 = 54;54/9=6 , and 6 + 1 = 7.
C is the answer
Both quantities can be solved straightforwardly with the equations. The first multiple of 7 between 50 and 100 is 56, and the last is 98. Thus: 98 − 56 = 42; ; 42/7=6 and 6 + 1 = 7. Another way to think about it is that 56 is the 8th multiple of 7, and 98 is the 14th multiple of 7. Now use the counting principle:
14 − 8 = 6 + 1 = 7
There are 7 multiples of 7 between 50 and 100. Similarly, the first multiple of 9 between 30 and 90 is 36, and the last is 90: 90 − 36 = 54;54/9=6 , and 6 + 1 = 7.
C is the answer
Re: The number of multiples of 7 between 50 and 100, inclusive
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28 Apr 2023, 11:16
28 Apr 2023, 11:16
what is the fundamentals behind this again? Is there something this references, in particular the logic for doing division by 7 + 1.
