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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x
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20 Oct 2018, 04:38
20 Oct 2018, 04:38
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Question Stats:
98% (00:43) correct
1% (00:44) wrong based on 51 sessions
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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?
A. 2x + 4
B. 3x − 2
C. 3x + 2
D. 4x − 2
E. 4x + 2
A. 2x + 4
B. 3x − 2
C. 3x + 2
D. 4x − 2
E. 4x + 2
Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x
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20 Oct 2018, 06:05
20 Oct 2018, 06:05
1
average = \(\frac{(2x + 3+ 5x − 4+ 6x-6+3x-1)}{4}\) = \(\frac{4(4x-2)}{4}\) = \(4x-2\)
So the answer is D
So the answer is D
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What is the average (arithmetic mean) of 2x + 3, 5x 4, 6x
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08 Jul 2021, 08:43
08 Jul 2021, 08:43
1
Theory: Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\)
We need to find the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1
Total Number of Values= 4
Sum of all the values= 2x + 3 + 5x − 4 + 6x − 6 + 3x − 1
= 2x + 5x + 6x + 3x + 3 - 4 - 6 - 1
= 16x - 8
=> Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\) = \(\frac{16x - 8 }{ 4}\)
= \(\frac{16x}{4}\) - \(\frac{8}{4}\)
= 4x - 2
So, Answer will be D
Hope it helps!
To learn more about Statistics watch the following video
We need to find the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1
Total Number of Values= 4
Sum of all the values= 2x + 3 + 5x − 4 + 6x − 6 + 3x − 1
= 2x + 5x + 6x + 3x + 3 - 4 - 6 - 1
= 16x - 8
=> Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\) = \(\frac{16x - 8 }{ 4}\)
= \(\frac{16x}{4}\) - \(\frac{8}{4}\)
= 4x - 2
So, Answer will be D
Hope it helps!
To learn more about Statistics watch the following video
