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A certain tin contains exactly 10 identically shaped gumdrop
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11 Aug 2018, 09:44
11 Aug 2018, 09:44
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A certain tin contains exactly 10 identically shaped gumdrops, of which 2 are cherry, 2 are lemon, 2 are grape, 2 are cinnamon and 2 are strawberry. If 2 gumdrops are randomly selected, one at a time and without replacement, what is the probability that the second gumdrop is the same flavor as the first?
A. \(\frac{1}{45}\)
B. \(\frac{1}{25}\)
C. \(\frac{1}{9}\)
D. \(\frac{1}{5}\)
E. \(\frac{2}{5}\)
A. \(\frac{1}{45}\)
B. \(\frac{1}{25}\)
C. \(\frac{1}{9}\)
D. \(\frac{1}{5}\)
E. \(\frac{2}{5}\)
Re: A certain tin contains exactly 10 identically shaped gumdrop
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11 Aug 2018, 10:03
11 Aug 2018, 10:03
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Carcass wrote:
A certain tin contains exactly 10 identically shaped gumdrops, of which 2 are cherry, 2 are lemon, 2 are grape, 2 are cinnamon and 2 are strawberry. If 2 gumdrops are randomly selected, one at a time and without replacement, what is the probability that the second gumdrop is the same flavor as the first?
A. \(\frac{1}{45}\)
B. \(\frac{1}{25}\)
C. \(\frac{1}{9}\)
D. \(\frac{1}{5}\)
E. \(\frac{2}{5}\)
A. \(\frac{1}{45}\)
B. \(\frac{1}{25}\)
C. \(\frac{1}{9}\)
D. \(\frac{1}{5}\)
E. \(\frac{2}{5}\)
Here,
for the first draw we pick any gumdrop,
Now we have remaining 9 gumdrop and selection a matching flavor with the first one = \(\frac{1}{9}\)
Re: A certain tin contains exactly 10 identically shaped gumdrop
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24 Nov 2018, 06:01
24 Nov 2018, 06:01
We also need to calculate the probability of selecting the 1st gumdrop , which will be 1/5 for any gumdeop and then multiply the probability of selecting the 2nd gumdrop , which should be 1/9.
To make it clear would you have also ignored the probability of selecting the 1st gumdrop if the numbers would have been different ?
To make it clear would you have also ignored the probability of selecting the 1st gumdrop if the numbers would have been different ?
