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If Juanita gives half of her bitcoins in a 1: 2 ratio to Pat
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10 Aug 2020, 10:48
10 Aug 2020, 10:48
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Question Stats:
51% (03:26) correct
48% (02:59) wrong based on 29 sessions
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If Juanita gives half of her bitcoins in a 1: 2 ratio to Pat and Svetlana, respectively, then Pat will have one fourth as many bitcoins as will Svetlana, who will in turn have twice as many bitcoins as will Juanita. If Pat currently has 2 bitcoins, then how many more bitcoins does Juanita currently have than Svetlana?
A. 8
B. 12
C. 20
D. 22
E. 24
A. 8
B. 12
C. 20
D. 22
E. 24
Re: If Juanita gives half of her bitcoins in a 1: 2 ratio to Pat
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11 Aug 2020, 03:45
11 Aug 2020, 03:45
Explanation pls
Re: If Juanita gives half of her bitcoins in a 1: 2 ratio to Pat
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11 Aug 2020, 04:16
11 Aug 2020, 04:16
1
Currently :
P : 2 bitcoin
S : y bitcoin
J : 6x bitcoin (Considering she has to divide it into 1/6th ( to give to P) and 2/6th (to give to S) )
After the transaction:
P : 2 + (6x/6) = 2 + x
S : y + (6x/3) = y + 2x
J : 6x - x - 2x = 3x
P = 1/4 * S
2 + x = 1/4 * (y + 2x)
y = 8 + 2x
S : y + 2x = 8 + 2x + 2x = 8 + 4x
S = 2 * J
4x + 8 = 2(3x)
x = 4
Thus, Currently
J - S = [6 * 4] - y = 24 - [8 + 2 *4] = 8
P : 2 bitcoin
S : y bitcoin
J : 6x bitcoin (Considering she has to divide it into 1/6th ( to give to P) and 2/6th (to give to S) )
After the transaction:
P : 2 + (6x/6) = 2 + x
S : y + (6x/3) = y + 2x
J : 6x - x - 2x = 3x
P = 1/4 * S
2 + x = 1/4 * (y + 2x)
y = 8 + 2x
S : y + 2x = 8 + 2x + 2x = 8 + 4x
S = 2 * J
4x + 8 = 2(3x)
x = 4
Thus, Currently
J - S = [6 * 4] - y = 24 - [8 + 2 *4] = 8
