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xy = –60, yz = –50
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06 May 2021, 04:21
06 May 2021, 04:21
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Question Stats:
67% (01:09) correct
32% (01:13) wrong based on 70 sessions
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\(xy = –60, yz = –50\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
xz |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: xy = –60, yz = –50
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06 May 2021, 04:50
06 May 2021, 04:50
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Carcass wrote:
\(xy = –60, yz = –50\)
Quantity A |
Quantity B |
xz |
0 |
Given:
\(xy = –60\)
\( yz = –50\)
Divide the top equation by the bottom equation to get: \(\frac{xy}{yz}=\frac{-60}{-50}\)
Simplify to get: \(\frac{x}{z}=\frac{6}{5}\)
Since \(\frac{x}{z}\) is POSITIVE, we know that x and z are the SAME SIGN (ie, both positive or both negative)
If x and z are the SAME SIGN, then the product xz is POSITIVE
Answer: A
Re: xy = –60, yz = –50
[#permalink]
07 May 2021, 01:16
07 May 2021, 01:16
2
Quote:
xy=–60,yz=–50
Multiplying the given equations
x*y^2* z = 3000
In the above product, as y^2 is always positive, the product xz has to be positive
xy > 0
A is correct
