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If x > 50,000, then the value of
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17 Mar 2023, 02:44
17 Mar 2023, 02:44
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50% (02:51) correct
50% (03:06) wrong based on 20 sessions
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If x > 50,000, then the value of \(\dfrac{2x^2+2x+1}{3x^2-3x+7}=\)
A. 1/3
B. 1/2
C. 2/3
D. 3/2
E. None of the above
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE INEQUALITIES
A. 1/3
B. 1/2
C. 2/3
D. 3/2
E. None of the above
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE INEQUALITIES
Re: If x > 50,000, then the value of
[#permalink]
14 Apr 2023, 02:13
14 Apr 2023, 02:13
1
Expert Reply
Simply
\(2x(x+1)+1/3x(x-1)+7\)
Notice how our first term is 2/3 plus some numerical extension of it: 2x * some number +1
3x * some number +7
Actually the base is 2/3
C is the answer
\(2x(x+1)+1/3x(x-1)+7\)
Notice how our first term is 2/3 plus some numerical extension of it: 2x * some number +1
3x * some number +7
Actually the base is 2/3
C is the answer
Re: If x > 50,000, then the value of
[#permalink]
07 Oct 2023, 05:28
07 Oct 2023, 05:28
Carcass wrote:
Simply
\(2x(x+1)+1/3x(x-1)+7\)
Notice how our first term is 2/3 plus some numerical extension of it: 2x * some number +1
3x * some number +7
Actually the base is 2/3
C is the answer
\(2x(x+1)+1/3x(x-1)+7\)
Notice how our first term is 2/3 plus some numerical extension of it: 2x * some number +1
3x * some number +7
Actually the base is 2/3
C is the answer
I don't understand this. If this is the case, then 2/5 = (2+5)/(5+5) , which is not valid. Can you please show this algebraically?
I tried to solve it by equating the given expression = 2/3 and the answer didn't return a solution where x > 50,000
