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M1, M2, M3, M4, M5, M6, M7 In the given sequence, each term is equal t
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29 Mar 2023, 00:23
29 Mar 2023, 00:23
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Question Stats:
50% (02:50) correct
50% (02:41) wrong based on 8 sessions
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\(M_1, M_2, M_3, M_4, M_5, M_6, M_7\)
In the given sequence, each term is equal to succeeding minus the constant d. If \(M_2+ M_4 + M_6 = 48\), what is the sum of \(M_1, M_3, M_5, M_7\)?
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In the given sequence, each term is equal to succeeding minus the constant d. If \(M_2+ M_4 + M_6 = 48\), what is the sum of \(M_1, M_3, M_5, M_7\)?
Show: ::
64
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Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
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Re: M1, M2, M3, M4, M5, M6, M7 In the given sequence, each term is equal t
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18 Jun 2023, 12:56
18 Jun 2023, 12:56
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First translate the word equation given in the passage:
\(M2=M3-d\)
Notice that:
\(M3=M4-d\)
Which implies:
\(M2=M4-2d\)
From this we can derive a general pattern:
\(Mi=Mk-(k-i)d\)
For all k>i
We can rewrite the target statement then as:
\(M1+M1-2d+M1-4d+M1-6d\)
\(4M1-12d=?\)
We can also rewrite the given statement:
\(M2+M4+M6=48\)
\(M1-d+M1-3d+M1-5d=48\)
\(3M1-9D=48\)
\(M1-3D=16\)
\(4M1-12D=16*4=64\)
Giving us the solution to our target question, 64.
\(M2=M3-d\)
Notice that:
\(M3=M4-d\)
Which implies:
\(M2=M4-2d\)
From this we can derive a general pattern:
\(Mi=Mk-(k-i)d\)
For all k>i
We can rewrite the target statement then as:
\(M1+M1-2d+M1-4d+M1-6d\)
\(4M1-12d=?\)
We can also rewrite the given statement:
\(M2+M4+M6=48\)
\(M1-d+M1-3d+M1-5d=48\)
\(3M1-9D=48\)
\(M1-3D=16\)
\(4M1-12D=16*4=64\)
Giving us the solution to our target question, 64.
General Discussion
Re: M1, M2, M3, M4, M5, M6, M7 In the given sequence, each term is equal t
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29 Mar 2023, 21:39
29 Mar 2023, 21:39
I think that is M2 + M4 + M6 ?
