It is not increasing exponentially. The questions states that each two tick are evenly spaced so all the tick are distant 2^6 - 2^5 = 32 or 2^5.

Let's assign some variables to some of the tick marks:


Let's first determine the distance between two tick marks.
$2^6-2^5 = 2^5(2-1) = 2^5$
So, the distance between consecutive tick marks is $2^5$

This means U = $2^5-2^5 = 0$
And V = $0-2^5 = -2^5$
And W = $-2^5-2^5 = -2(2^5)$
And X = $-2(2^5)-2^5 = -3(2^5)$

Answer: D

The difference between each even space = 2^6 - 2^5 = 2^5 = 32.

Since X is 4 'even spaces' to the left of 2^5 = 32, then it is 4*32 units less than 32.

4*32 units less than 32 is also 3*32 units less than zero when you remove one 32 which is -96.

X = -96

Prime factorisation of -96 is as follows:

x = - 96
= -(2*48)
= -2*2*24
= -2*2*2*12
= -2*2*2*2*6
= -2*2*2*2*2*3
= -2^5*3
= -3*2^5

The correct answer is D.

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.