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x=a ius a root of the equation

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thelastzedi
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x=a ius a root of the equation [#permalink] New post   Updated on: 11 Apr 2023, 09:38
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\(x=a\) is a root of the equation \(x^2−6x+1=0\)

Quantity A
Quantity B
\(a^2+a^{−2} \)
35



a) Quantity A is greater
b) Quantity B is greater
c) The two quantities are equal
d) The relationship cannot be determined from the information given
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B

Originally posted by thelastzedi on 11 Apr 2023, 08:53.
Last edited by Carcass on 11 Apr 2023, 09:38, edited 1 time in total.
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Carcass
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Re: x=a ius a root of the equation [#permalink] New post   11 Apr 2023, 09:31
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The question must be posted under the QCQ forum NOT in meet and greet

Also must be formatted in the right manner. Please follow the rules https://gre.myprepclub.com/forum/rules- ... -1083.html

I move the post in the right section
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Re: x=a ius a root of the equation [#permalink] New post   11 Apr 2023, 09:37
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The root of the equation are

x=a=-3

or

x=a=2

In both cases, substituting we do know that B is always greater than A

B is the answer
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thelastzedi
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Re: x=a ius a root of the equation [#permalink] New post   11 Apr 2023, 10:23
Carcass wrote:
The root of the equation are

x=a=-3

or

x=a=2

In both cases, substituting we do know that B is always greater than A

B is the answer



How do you calculate the roots ?
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Re: x=a ius a root of the equation [#permalink] New post   11 Apr 2023, 10:49
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Roots of Quadratic Equation

https://www.cuemath.com/algebra/roots-o ... -equation/
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gmatclubot
Re: x=a ius a root of the equation [#permalink]
11 Apr 2023, 10:49
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