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x=a ius a root of the equation
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Updated on: 11 Apr 2023, 09:38
Updated on: 11 Apr 2023, 09:38
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Question Stats:
66% (01:31) correct
33% (01:56) wrong based on 6 sessions
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\(x=a\) is a root of the equation \(x^2−6x+1=0\)
a) Quantity A is greater
b) Quantity B is greater
c) The two quantities are equal
d) The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(a^2+a^{−2} \) |
35 |
a) Quantity A is greater
b) Quantity B is greater
c) The two quantities are equal
d) The relationship cannot be determined from the information given
Originally posted by thelastzedi on 11 Apr 2023, 08:53.
Last edited by Carcass on 11 Apr 2023, 09:38, edited 1 time in total.
Last edited by Carcass on 11 Apr 2023, 09:38, edited 1 time in total.
UPDATED
Re: x=a ius a root of the equation
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11 Apr 2023, 09:31
11 Apr 2023, 09:31
Expert Reply
The question must be posted under the QCQ forum NOT in meet and greet
Also must be formatted in the right manner. Please follow the rules https://gre.myprepclub.com/forum/rules- ... -1083.html
I move the post in the right section
Also must be formatted in the right manner. Please follow the rules https://gre.myprepclub.com/forum/rules- ... -1083.html
I move the post in the right section
Re: x=a ius a root of the equation
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11 Apr 2023, 09:37
11 Apr 2023, 09:37
Expert Reply
The root of the equation are
x=a=-3
or
x=a=2
In both cases, substituting we do know that B is always greater than A
B is the answer
x=a=-3
or
x=a=2
In both cases, substituting we do know that B is always greater than A
B is the answer
