GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If a > x > y , which of the following must be true ? a > 0 x > y a2x
[#permalink]
20 Mar 2023, 05:17
20 Mar 2023, 05:17
Expert Reply
00:00
Question Stats:
76% (01:17) correct
23% (01:34) wrong based on 17 sessions
Hide Show timer Statistics
If \(a > x > y\) , which of the following must be true ?
Indicate all that apply
\(a > 0\)
\(x > –y\)
\(a^2x ≥ a^2y\)
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE INEQUALITIES
Indicate all that apply
\(a > 0\)
\(x > –y\)
\(a^2x ≥ a^2y\)
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE INEQUALITIES
Re: If a > x > y , which of the following must be true ? a > 0 x > y a2x
[#permalink]
11 Apr 2023, 10:55
11 Apr 2023, 10:55
Expert Reply
1) a could be also negative
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
Re: If a > x > y , which of the following must be true ? a > 0 x > y a2x
[#permalink]
07 Oct 2023, 06:22
07 Oct 2023, 06:22
Carcass wrote:
1) a could be also negative
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
2) x+y>0 we do know that is positive but this is not guaranteed. We do not the sign of x and y
3) dividing both side by a^2 what is left is \(x \geq y\) and is given that x>y
This is the only true option
For 3) after dividing by a^2, we get x >= y. This implies that x could be = y which is in violation of the given constraint. Therefore, none of the given options is correct.
