GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
Re: The construction of a room costs $10,000, which includes cementing cos
[#permalink]
12 Apr 2023, 20:38
Let's first calculate the total cost by summing up the costs of cementing, wood work, and miscellaneous:
Total cost = Cementing cost + Wood work cost + Miscellaneous cost
Total cost = $6,000 + $1,500 + Miscellaneous cost
Total cost = $7,500 + Miscellaneous cost
Next, we are given that the total cost is $10,000, so we can write the equation:
$7,500 + Miscellaneous cost = $10,000
Now, let's isolate the Miscellaneous cost by subtracting $7,500 from both sides of the equation:
Miscellaneous cost = $10,000 - $7,500
Miscellaneous cost = $2,500
So, the miscellaneous cost is $2,500.
Now, let's calculate the percentage of the total cost that the miscellaneous cost represents:
Percentage of total cost = (Miscellaneous cost / Total cost) x 100
Percentage of total cost = ($2,500 / $10,000) x 100
Percentage of total cost = 25%
Therefore, the correct answer is option (c) 25%.