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In a mixture having 35% milk and rest water, how many litres of water
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03 Apr 2023, 01:19
03 Apr 2023, 01:19
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75% (02:06) correct
25% (01:36) wrong based on 16 sessions
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In a mixture having 35% milk and rest water, how many litres of water must be added to reduce the milk percentage to 20% of the total volume, if the volume of the initial mixture is 100 litres?
13 litres
36 litres
52 litres
65 litres
75 litres
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13 litres
36 litres
52 litres
65 litres
75 litres
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
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Re: In a mixture having 35% milk and rest water, how many litres of water
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12 Apr 2023, 20:39
12 Apr 2023, 20:39
3
Expert Reply
Let's break down the problem step by step.
Initial milk percentage in the mixture = 35%
Initial water percentage in the mixture = 100% - 35% = 65%
Given that the initial volume of the mixture is 100 litres, we can calculate the initial volume of milk and water in the mixture:
Initial volume of milk = 35% of 100 litres = 35 litres
Initial volume of water = 65% of 100 litres = 65 litres
Now, let's assume x litres of water need to be added to reduce the milk percentage to 20% of the total volume.
After adding x litres of water, the total volume of the mixture becomes (100 + x) litres.
The volume of milk in the mixture remains the same at 35 litres, and the volume of water becomes (65 + x) litres.
According to the given condition, the milk percentage in the mixture after adding x litres of water should be 20%. We can write this as an equation:
Volume of milk / Total volume of mixture after adding x litres of water = 20%
Plugging in the values, we get:
35 / (100 + x) = 20/100
Cross-multiplying, we get:
35 x 100 = 20 x (100 + x)
3500 = 2000 + 20x
Subtracting 2000 from both sides, we get:
1500 = 20x
Dividing both sides by 20, we get:
x = 75
So, 75 litres of water must be added to reduce the milk percentage to 20% of the total volume.
Therefore, the correct answer is option (e) 75 litres.
Initial milk percentage in the mixture = 35%
Initial water percentage in the mixture = 100% - 35% = 65%
Given that the initial volume of the mixture is 100 litres, we can calculate the initial volume of milk and water in the mixture:
Initial volume of milk = 35% of 100 litres = 35 litres
Initial volume of water = 65% of 100 litres = 65 litres
Now, let's assume x litres of water need to be added to reduce the milk percentage to 20% of the total volume.
After adding x litres of water, the total volume of the mixture becomes (100 + x) litres.
The volume of milk in the mixture remains the same at 35 litres, and the volume of water becomes (65 + x) litres.
According to the given condition, the milk percentage in the mixture after adding x litres of water should be 20%. We can write this as an equation:
Volume of milk / Total volume of mixture after adding x litres of water = 20%
Plugging in the values, we get:
35 / (100 + x) = 20/100
Cross-multiplying, we get:
35 x 100 = 20 x (100 + x)
3500 = 2000 + 20x
Subtracting 2000 from both sides, we get:
1500 = 20x
Dividing both sides by 20, we get:
x = 75
So, 75 litres of water must be added to reduce the milk percentage to 20% of the total volume.
Therefore, the correct answer is option (e) 75 litres.
Re: In a mixture having 35% milk and rest water, how many litres of water
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02 Jan 2024, 06:04
02 Jan 2024, 06:04
1
as we can see the the milk is constant and we are only adding water to drop the percent of milk in new solution(when we add water)
next we know 35 lit in 100 lit is milk now when water is added the solution will diluted but milk will remain same ( because we only added water ) so 20% solution represent the milk and we know that milk quantity is fixed i.e 35 lit
therefore if 35lit corresponds to 20% then 100% will correspond to ?? [175 lit = equal to total new mixture ) [ how i got 175 ? ....... if 20% = 35 lit then 1% = (35/20) hence 100% = (35/20)*100 = 175]
we know that our initial solution is 100 and new solution is 175 therefore quantity of water added must be ( 175-100 = 75) lit
next we know 35 lit in 100 lit is milk now when water is added the solution will diluted but milk will remain same ( because we only added water ) so 20% solution represent the milk and we know that milk quantity is fixed i.e 35 lit
therefore if 35lit corresponds to 20% then 100% will correspond to ?? [175 lit = equal to total new mixture ) [ how i got 175 ? ....... if 20% = 35 lit then 1% = (35/20) hence 100% = (35/20)*100 = 175]
we know that our initial solution is 100 and new solution is 175 therefore quantity of water added must be ( 175-100 = 75) lit
