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Re: If x + y = 10, and y + z = 20 and x + z = 30, then what percent of x +
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15 Apr 2023, 21:03
Let's solve the given equations to find the values of x, y, and z:
Given:
x + y = 10 ---(1)
y + z = 20 ---(2)
x + z = 30 ---(3)
We can rearrange equation (1) to solve for x:
x = 10 - y ---(4)
We can rearrange equation (2) to solve for z:
z = 20 - y ---(5)
We can rearrange equation (3) to solve for x:
x = 30 - z ---(6)
Now, let's substitute the values of x and z from equations (4) and (5) into equation (6):
10 - y = 30 - (20 - y)
Simplifying further:
10 - y = 30 - 20 + y
Combining like terms:
10 - y = 10 + y
Adding y to both sides:
10 = 10 + 2y
Subtracting 10 from both sides:
0 = 2y
Dividing both sides by 2:
0 = y
Now we can substitute the value of y into equations (1), (2), and (3) to find the values of x and z:
x + 0 = 10
x = 10
0 + z = 20
z = 20
x + z = 30
10 + 20 = 30
So, we have x = 10, y = 0, and z = 20.
Now let's calculate the percentage of x + y with respect to x + y + z:
x + y = 10 + 0 = 10
x + y + z = 10 + 0 + 20 = 30
Percentage of x + y with respect to x + y + z:
(10 / 30) * 100 = 33.33%
So, the correct answer is "100/3%".