GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
( x + 3)(x 2)^2(x23)(2x 4) = 0
[#permalink]
17 Apr 2023, 01:17
17 Apr 2023, 01:17
Expert Reply
6
Bookmarks
00:00
Question Stats:
44% (01:06) correct
55% (01:11) wrong based on 67 sessions
Hide Show timer Statistics
\(( x + 3)(x – 2)^2(x^2–3)(2x – 4) = 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Quantity A |
Quantity B |
The number of integer values of x for which above equation is true |
3 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Re: ( x + 3)(x 2)^2(x23)(2x 4) = 0
[#permalink]
25 May 2023, 13:23
25 May 2023, 13:23
Expert Reply
OE
We have to compare
Quantity A: The number of integer values of x for which above equation is true
Quantity B: 3
If the product of numbers is 0; then, at least one of them has to be 0.
Therefore, either 𝑥 + 3 = 0 or 𝑥 − 2 = 0 or 𝑥
2 − 3 = 0 or 2𝑥 – 4 = 0
i.e. 𝑥 = −3 or 𝑥 = 2 or 𝑥^2 = 3 or 2𝑥 = 4
Since, we want to find the number of integer values of x from the above equations,
𝑥^2 = 3 is giving me 𝑥 = ±√3 which is not integer.
Also, 2𝑥 = 4 gives us 𝑥 = 2.
So, we can see that the integer values of 𝑥 are -3 and 2.
Hence, quantity B is greater.
Ans. (B)
We have to compare
Quantity A: The number of integer values of x for which above equation is true
Quantity B: 3
If the product of numbers is 0; then, at least one of them has to be 0.
Therefore, either 𝑥 + 3 = 0 or 𝑥 − 2 = 0 or 𝑥
2 − 3 = 0 or 2𝑥 – 4 = 0
i.e. 𝑥 = −3 or 𝑥 = 2 or 𝑥^2 = 3 or 2𝑥 = 4
Since, we want to find the number of integer values of x from the above equations,
𝑥^2 = 3 is giving me 𝑥 = ±√3 which is not integer.
Also, 2𝑥 = 4 gives us 𝑥 = 2.
So, we can see that the integer values of 𝑥 are -3 and 2.
Hence, quantity B is greater.
Ans. (B)
Re: ( x + 3)(x 2)^2(x23)(2x 4) = 0
[#permalink]
26 Sep 2024, 06:06
26 Sep 2024, 06:06
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
