GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The price of a vanilla candy is $x less than twice the cost of a choco
[#permalink]
17 Apr 2023, 01:20
17 Apr 2023, 01:20
Expert Reply
4
Bookmarks
00:00
Question Stats:
67% (03:15) correct
32% (03:19) wrong based on 34 sessions
Hide Show timer Statistics
The price of a vanilla candy is $x less than twice the cost of a chocolate candy. Their combined cost is less than the cost of 3 vanilla candies.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Quantity A |
Quantity B |
Cost of 4 chocolate candies |
8/3 x |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE EQUATIONS
Re: The price of a vanilla candy is $x less than twice the cost of a choco
[#permalink]
17 Apr 2023, 07:24
17 Apr 2023, 07:24
4
A bit laborious, but it gives the answer.
VC = Vanilla Candy
CC = Chocolate Candy
The price of a vanilla candy is $x less than twice the cost of a chocolate candy.
VC = 2CC - X --- (1)
Their combined cost is less than the cost of 3 vanilla candies.
VC + CC < 3VC --- (2)
substituting (1) in (2)
2CC - X + CC < 3VC
3CC - X < 3VC
3CC - 3VC < X
3CC - 3(2CC - X) < X
3CC - 6CC + 3X < X
-3CC + 3X < X
-3CC < X - 3X
-3CC < -2X
multiplying throughout by - 1
3CC > 2X
Since Quantity B is (8/3)X, we divide throughout by 3/4 to get
3CC/(3/4) > 2X/(3/4)
4CC > 8/3X
Quantity A is greater than Quantity B
Choice A
VC = Vanilla Candy
CC = Chocolate Candy
The price of a vanilla candy is $x less than twice the cost of a chocolate candy.
VC = 2CC - X --- (1)
Their combined cost is less than the cost of 3 vanilla candies.
VC + CC < 3VC --- (2)
substituting (1) in (2)
2CC - X + CC < 3VC
3CC - X < 3VC
3CC - 3VC < X
3CC - 3(2CC - X) < X
3CC - 6CC + 3X < X
-3CC + 3X < X
-3CC < X - 3X
-3CC < -2X
multiplying throughout by - 1
3CC > 2X
Since Quantity B is (8/3)X, we divide throughout by 3/4 to get
3CC/(3/4) > 2X/(3/4)
4CC > 8/3X
Quantity A is greater than Quantity B
Choice A
Re: The price of a vanilla candy is $x less than twice the cost of a choco
[#permalink]
29 Nov 2024, 02:14
29 Nov 2024, 02:14
1
lets form 2 equations from the given data
assume cost of 1 vanilla candy as Cv and cost of 1 chocolate candy as Cc
1 vanilla candy is $x less than 2 times times the cost of chocolate candy
so Cv = 2Cc - x --- 1
cost of 3 vanilla candies is greater than cost of 1 vanilla candy and 1 chocolate candy
3Cv > Cc + Cv
2Cv > Cc ---2
put equation 1 in equation 2, we get
4Cc -2x > Cc
3Cc > 2x
divide by 3 and multiply by 4
we get 4Cc > (8/3) x
option A is the right answer
assume cost of 1 vanilla candy as Cv and cost of 1 chocolate candy as Cc
1 vanilla candy is $x less than 2 times times the cost of chocolate candy
so Cv = 2Cc - x --- 1
cost of 3 vanilla candies is greater than cost of 1 vanilla candy and 1 chocolate candy
3Cv > Cc + Cv
2Cv > Cc ---2
put equation 1 in equation 2, we get
4Cc -2x > Cc
3Cc > 2x
divide by 3 and multiply by 4
we get 4Cc > (8/3) x
option A is the right answer
