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Paul went to office at an average speed of 30km/hr for the first half

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Paul went to office at an average speed of 30km/hr for the first half [#permalink] New post   20 Apr 2023, 15:22
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Paul went to office at an average speed of 30km/hr for the first half and 40km/hr for the remaining half distance whereas Michel covers the same distance as Paul with the same speeds of 30km/hr and 40km/hr but the ratio of the distances was 2 : 3 for the respective speeds


Quantity A
Quantity B
Paul’s average speed for the entire distance
Michel’s average speed for the entire distance



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.




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B
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Midhilesh489
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Re: Paul went to office at an average speed of 30km/hr for the first half [#permalink] New post   20 Apr 2023, 17:56
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Let total distance = 100

Paul's avg speed = 100/(50/30 + 50/40) = 2 * 30 * 40/70 = 240/7 = 34.xx

Michel's avg speed = 100/(40/30 + 60/40) = 4/3 + 3/2 = 600/17 = 35.xx

B > A
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Re: Paul went to office at an average speed of 30km/hr for the first half [#permalink] New post   19 Jun 2024, 22:19
can this be D since the ratio of distance travelled by Paul is not mentioned? any explanation...
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Re: Paul went to office at an average speed of 30km/hr for the first half [#permalink] New post   19 Jun 2024, 23:07
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I am not sure to get what you meant. The ration of P to M is mentioned and it is 2/3

You can solve also conceptually the problem

P is 30-------------40 and its ration is 2 so the exact center is 35

M is 30-------------40 and its ration is 3 so the center is 23

This means that the average speed of M is greater than that of P

M >P

B > A
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Re: Paul went to office at an average speed of 30km/hr for the first half [#permalink]
19 Jun 2024, 23:07
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