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A circle is inscribed in a square shown above. If the area of the circ
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02 May 2023, 07:17
02 May 2023, 07:17
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75% (01:28) correct
25% (00:43) wrong based on 12 sessions
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A circle is inscribed in a square shown above. If the area of the circle is x sq. units, what is the length of diagonal of square in terms of x?
\(\sqrt{\frac{2x}{\pi}}\)
\(2 \sqrt{\frac{2x}{\pi}}\)
\(2 \sqrt{\frac{x}{\pi}}\)
\(\sqrt{\frac{x}{\pi}}\)
\(3 \sqrt{\frac{2x}{\pi}}\)
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Re: A circle is inscribed in a square shown above. If the area of the circ
[#permalink]
28 May 2023, 00:38
28 May 2023, 00:38
Expert Reply
OE
Let the side of the square be ‘s’
And, Let the radius of the circle be ‘r’
So, s = 2r
Now, area of circle = πr^2 = x
r = √𝑥/𝜋
So, s = 2 ×√𝑥/𝜋
Diagonal of square = √2 × (side) = √2 × (2 × √𝑥/𝜋) = 2 √2𝑥/𝜋
Ans. (B)
Let the side of the square be ‘s’
And, Let the radius of the circle be ‘r’
So, s = 2r
Now, area of circle = πr^2 = x
r = √𝑥/𝜋
So, s = 2 ×√𝑥/𝜋
Diagonal of square = √2 × (side) = √2 × (2 × √𝑥/𝜋) = 2 √2𝑥/𝜋
Ans. (B)
gmatclubot
Re: A circle is inscribed in a square shown above. If the area of the circ [#permalink]
28 May 2023, 00:38
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