OE

Let us draw a perpendicular from E which intersects AB at F.




Since ABCD is a square, EF divides it into two rectangles BCEF and FEDA.
As we know that a diagonal divides the rectangle into two equal areas.

So, BE being a diagonal of BCEF divides it in two equal regions, say X.
Similarly, AD being a diagonal of FEDA divides it into two equal regions, say Y.




Area of the shaded region X + Y

Area of the unshaded region X + Y

C is the answer