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In a cuboid with dimensions 5 × 10 × 10, what is the shortest distance
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19 Jun 2023, 05:45
19 Jun 2023, 05:45
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75% (01:54) correct
25% (01:50) wrong based on 8 sessions
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In a cuboid with dimensions 5 × 10 × 10, what is the shortest distance from the centre of the cuboid and the vertex?
A. 5
B. 7.5
C. 10
D. \(5 \sqrt{5}\)
E. \(5 \sqrt{6}\)
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
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\(\Longrightarrow\) GRE GEOMETRY
A. 5
B. 7.5
C. 10
D. \(5 \sqrt{5}\)
E. \(5 \sqrt{6}\)
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE GEOMETRY
Re: In a cuboid with dimensions 5 × 10 × 10, what is the shortest distance
[#permalink]
19 Jun 2023, 06:36
19 Jun 2023, 06:36
1
Use 3D Pythagoras to determine the distance between any two vertices:
\(5^2+10^2+10^2=x^2\)
\(x^2=225\)
\(x=15\)
And then just cut it into two, as 15 is the distance between any two vertices - 7.5
B
\(5^2+10^2+10^2=x^2\)
\(x^2=225\)
\(x=15\)
And then just cut it into two, as 15 is the distance between any two vertices - 7.5
B
gmatclubot
Re: In a cuboid with dimensions 5 × 10 × 10, what is the shortest distance [#permalink]
19 Jun 2023, 06:36
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