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In the figure, what is the area of triangle BCD given

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GreenlightTestPrep
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In the figure, what is the area of triangle BCD given [#permalink] New post   10 Jan 2019, 12:59
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In the figure above, the area of triangle ADE is 16 and the area of triangle CDE is 12. What is the area of triangle BCD?

Answer:
Show: ::
28
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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   10 Jan 2019, 19:44
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GreenlightTestPrep wrote:
Image

In the figure above, the area of triangle ADE is 16 and the area of triangle CDE is 12. What is the area of triangle BCD?

Answer:
Show: ::
20



If we add ADE and CDE, we get triangle ADC, which has an area of 28, which is the sum of the areas of ADE and CDE, 16+12.

Now if we compare triangle ACD with triangle BCD, the base is CD, common to both AND the height is also the same as both triangles between two parallel lines, AB and CD.
With base and height the same, the area of the two triangles will be the same, so area of BCD is also 28.

Brent, could you please check the OA as it is given 20
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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   11 Jan 2019, 09:49
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GreenlightTestPrep wrote:
Image

In the figure above, the area of triangle ADE is 16 and the area of triangle CDE is 12. What is the area of triangle BCD?

Answer:
Show: ::
28


∆ADC is comprised of 2 regions: ∆ADE and ∆CDE
We're told that ∆ADE and ∆CDE have areas 16 ans 12 respectively.
So, the area of ∆ADC = 16 + 12 = 28
Image


First recognize that ∆ADC and ∆BCD both have the same base.
Also, if we let h = the height of ∆ADC, then ∆BCD also has height h
Image

area of triangle = (base)(height)/2
So, if ∆ADC and ∆BCD have the same base and the same height, then they must have the same area.

So, if the area of ∆ADC is 28, then the area of ∆BCD must also be 28


Answer: 28

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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   11 Jul 2021, 08:16
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GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
Image

In the figure above, the area of triangle ADE is 16 and the area of triangle CDE is 12. What is the area of triangle BCD?

Answer:
Show: ::
28


∆ADC is comprised of 2 regions: ∆ADE and ∆CDE
We're told that ∆ADE and ∆CDE have areas 16 ans 12 respectively.
So, the area of ∆ADC = 16 + 12 = 28
Image


First recognize that ∆ADC and ∆BCD both have the same base.
Also, if we let h = the height of ∆ADC, then ∆BCD also has height h
Image

area of triangle = (base)(height)/2
So, if ∆ADC and ∆BCD have the same base and the same height, then they must have the same area.

So, if the area of ∆ADC is 28, then the area of ∆BCD must also be 28


Answer: 28

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In the figure, what is the area of triangle ADB given that the area of triangle ACE is 4 and the area of triangle CDE is 3?
Give your answer as a fraction.

can you please solve it for me
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File comment: In the figure, what is the area of triangle ADB given that the area of triangle ACE is 4 and the area of triangle CDE is 3?
Give your answer as a fraction.
figure geomentry.png
figure geomentry.png [ 21.92 KiB | Viewed 4832 times ]

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mrk9414
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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   11 Jul 2021, 08:30
mrk9414 wrote:
GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
Image

In the figure above, the area of triangle ADE is 16 and the area of triangle CDE is 12. What is the area of triangle BCD?

Answer:
Show: ::
28


∆ADC is comprised of 2 regions: ∆ADE and ∆CDE
We're told that ∆ADE and ∆CDE have areas 16 ans 12 respectively.
So, the area of ∆ADC = 16 + 12 = 28
Image


First recognize that ∆ADC and ∆BCD both have the same base.
Also, if we let h = the height of ∆ADC, then ∆BCD also has height h
Image

area of triangle = (base)(height)/2
So, if ∆ADC and ∆BCD have the same base and the same height, then they must have the same area.

So, if the area of ∆ADC is 28, then the area of ∆BCD must also be 28


Answer: 28

RELATED VIDEO FROM OUR COURSE


In the figure, what is the area of triangle ADB given that the area of triangle ACE is 4 and the area of triangle CDE is 3?
Give your answer as a fraction.

can you please solve it for me


Sir, I kindly request you to please go through the question

as inverting the figure changes a lot and it's asked for another triangle that too infraction.

and the answer is supposed to be 28/3, would really kind of you if you could explain to me
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In the figure, what is the area of triangle BCD given [#permalink] New post   11 Jul 2021, 09:54
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It is correct indeed. \(28\) is the answer.

The base of both the triangle is same. Hence the formula used is correct.

Can you please post your way of reaching \(\frac{28}{3}\)? Perhaps the mistake can be evaluated better.

Regards

mrk9414 wrote:
Sir, I kindly request you to please go through the question

as inverting the figure changes a lot and it's asked for another triangle that too infraction.

and the answer is supposed to be 28/3, would really kind of you if you could explain to me
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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   11 Jul 2021, 12:01
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rx10 wrote:
It is correct indeed. \(28\) is the answer.

The base of both the triangle is same. Hence the formula used is correct.

Can you please post your way of reaching \(\frac{28}{3}\)? Perhaps the mistake can be evaluated better.

Regards

mrk9414 wrote:
Sir, I kindly request you to please go through the question

as inverting the figure changes a lot and it's asked for another triangle that too infraction.

and the answer is supposed to be 28/3, would really kind of you if you could explain to me




In the figure, what is the area of triangle ADB given that the area of triangle ACE is 4 and the area of triangle CDE is 3?
Give your answer as a fraction.

can you please solve it for me as the question is a bit different would request you to through and figure and values in the question are different
Attachments

File comment: In the figure, what is the area of triangle ADB given that the area of triangle ACE is 4 and the area of triangle CDE is 3?
Give your answer as a fraction.
figure geomentry.png
figure geomentry.png [ 21.92 KiB | Viewed 4713 times ]

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rx10
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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   11 Jul 2021, 19:12
It's a new question. Please create a new post. Here : https://gre.myprepclub.com/forum/posting.p ... =post&f=19
You should not post sub questions.

And please refer to this while posting : https://gre.myprepclub.com/forum/how-to-po ... 12752.html

mrk9414 wrote:
Sir, I kindly request you to please go through the question

as inverting the figure changes a lot and it's asked for another triangle that too infraction.

and the answer is supposed to be 28/3, would really kind of you if you could explain to me

In the figure, what is the area of triangle ADB given that the area of triangle ACE is 4 and the area of triangle CDE is 3?
Give your answer as a fraction.

can you please solve it for me as the question is a bit different would request you to through and figure and values in the question are different
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Re: In the figure, what is the area of triangle BCD given [#permalink] New post   27 Jun 2023, 10:09
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Re: In the figure, what is the area of triangle BCD given [#permalink]
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