P is a two digit positive integer, obtained by reversing the order of digits of a positive integer Q

Let Q be the two digit number xy
=> Q = 10x + y (e.x 21 = 10*2 + 1)

P is obtained by reversing the digits of Q
=> P = yx = 10y + x

If P-Q is divisible by 6
P - Q = 10x + y - (10y + x) = 9x - 9y = 9(x-y)
Now, P-Q is divisible by 6
=> 9*(x-y) is divisible by 6
=> x-y should be even number as for divisibility by 6 we need a 3 and 2 and 9(x-y) has a 3 in 9
=> Either both x and y are odd or both are even as (Odd-Odd = Even and Even-Even = Even)

So Both P and Q are either odd or both are even
In any case P + Q will be Even as (Odd+Odd = Even and Even + Even = Even)

Only, even choice is 88

So, Answer will be B
Hope it helps!