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GRE Math Challenge #141-m is a positive integer less than 4

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sandy
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GRE Math Challenge #141-m is a positive integer less than 4 [#permalink] New post   Updated on: 20 Feb 2020, 16:29
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A
B
C
D

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m is a positive integer less than 4.

Quantity A
Quantity B
(m+2)2
mm+2


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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Originally posted by sandy on 15 May 2015, 11:43.
Last edited by Carcass on 20 Feb 2020, 16:29, edited 1 time in total.
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GreenlightTestPrep
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Re: GRE Math Challenge #141 [#permalink] New post   15 May 2015, 13:45
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sandy wrote:
m is a positive integer less than 4.

Quantity A: (m+2)2
Quantity B: m^(^m^+^2^)


NOTE: m is a positive integer less than 4
This means that there are only 3 possible values for (m = 1, 2 or 3)
So, rather than perform any algebraic manipulations, let's just TEST all 3 values of m.

m = 1
Quantity A: (1+2)^2 = = 3^2 = 9
Quantity B: 1^(1+2) = 1^3 = 1
In this case, quantity A is greater.

m = 2
Quantity A: (2+2)^2 = = 4^2 = 16
Quantity B: 2^(2+2) = 2^4 = 16
In this case, quantity A is equal to quantity B.

STOP!
At this point, we can conclude that the correct answer is
Show: ::
D


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Brent
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Carcass
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Re: GRE Math Challenge #141-m is a positive integer less than 4 [#permalink] New post   02 Jan 2022, 07:29
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Re: GRE Math Challenge #141-m is a positive integer less than 4 [#permalink]
02 Jan 2022, 07:29
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