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The line y=-8/7x is graphed on the rectangular coordinate axes.

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Carcass
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The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   Updated on: 30 Mar 2024, 00:51
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GRE The line y=-87x is graphed on the rectangular coordinate axes..jpg
GRE The line y=-87x is graphed on the rectangular coordinate axes..jpg [ 7.46 KiB | Viewed 4375 times ]



The line \(y=-\frac{8}{7}x+1\) is graphed on the rectangular coordinate axes.


Quantity A
Quantity B
OR
OP



A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.


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B

Originally posted by Carcass on 02 Jun 2023, 22:43.
Last edited by Carcass on 30 Mar 2024, 00:51, edited 2 times in total.
Fixed typo
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TusharM1998
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   26 Jun 2023, 02:09
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But the equation says y = -8/7*x right? in that case as y-intercept of line is 0, line will pass through origin. What am I not understanding?
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The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   05 Jun 2023, 04:00
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OE


The y-intercept, or b, in this case is 1. That means the line crosses the
y-axis at 1. So the coordinates of point P are (0, 1). Now we have to
determine the coordinates of point R. We know the y-coordinate is 0,
so let’s stick that into the equation (the slope and the y-intercept are
constant; they don’t change).

y = mx + b

\(0=-\frac{8}{7}x+1\)

Solving

\(x=\frac{7}{8}
\)

So the coordinates of point R are (7/8 , 0). That means OR, in Quantity A, is equal to , and OP, in Quantity B, is equal to 1. The answer is (B).
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   31 Aug 2023, 12:39
1
Normally, y = mx + c is the equation of a line, but in this case it is y = (-8/7)x which means that the 'c' or the 'y-intercept' is 0. Which also means that this line passes through the origin with a slope of -8/7..

We can right away start by putting values of 'y' here,
y = 1 x = -7/8
y = 2 x = -14/8
...
Whatever you do, the x value stays negative, and in the diagram the X value is the OR and y value is OP, so OP must be greater
Thus, B is the answer
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   29 Mar 2024, 07:16
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The math is not mathing for this problem and the solution provided is also unclear
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   29 Mar 2024, 10:04
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You are right.

Because in one version in the stem, the +1 was not mentioned, but yes in the solution.

I fixed the question
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   29 Mar 2024, 18:37
Carcass wrote:
OE


The y-intercept, or b, in this case is 1. That means the line crosses the
y-axis at 1. So the coordinates of point P are (0, 1). Now we have to
determine the coordinates of point R. We know the y-coordinate is 0,
so let’s stick that into the equation (the slope and the y-intercept are
constant; they don’t change).

y = mx + b

\(0=-\frac{8}{7x}+1\)

Solving

\(x=\frac{7}{8}
\)

So the coordinates of point R are (7/8 , 0). That means OR, in Quantity A, is equal to , and OP, in Quantity B, is equal to 1. The answer is (B).



Based on this logis, then x should be 8/7 not 7/8, that means the correct answer is A and not B.
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The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   30 Mar 2024, 00:52
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It is not \(y=-\frac{8}{7x}\) BUT \(-\frac{8}{7}\) x

Sometimes latex code is messy I know
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   30 Mar 2024, 05:44
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Shevchenko wrote:
Carcass wrote:
OE


The y-intercept, or b, in this case is 1. That means the line crosses the
y-axis at 1. So the coordinates of point P are (0, 1). Now we have to
determine the coordinates of point R. We know the y-coordinate is 0,
so let’s stick that into the equation (the slope and the y-intercept are
constant; they don’t change).

y = mx + b

\(0=-\frac{8}{7x}+1\)

Solving

\(x=\frac{7}{8}
\)

So the coordinates of point R are (7/8 , 0). That means OR, in Quantity A, is equal to , and OP, in Quantity B, is equal to 1. The answer is (B).



Based on this logis, then x should be 8/7 not 7/8, that means the correct answer is A and not B.



Ahhh... I now see why I failed the question. Thanks.
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   30 Mar 2024, 06:02
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink] New post   27 May 2025, 09:52
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Re: The line y=-8/7x is graphed on the rectangular coordinate axes. [#permalink]
27 May 2025, 09:52
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