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A pomegranate grower packages pomegranates in 10-pound and 20-pound b
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14 Jun 2023, 16:56
14 Jun 2023, 16:56
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Question Stats:
26% (02:06) correct
73% (02:08) wrong based on 60 sessions
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A pomegranate grower packages pomegranates in 10-pound and 20-pound boxes. If the grower fills more than twice as many 20-pound boxes as lO-pound boxes, which of the following could be the percentage of pomegranates, by weight, that are packaged in 10-pound boxes?
(A) 15%
(B) 2 0 %
(C) 25%
(D) 4 0 %
(E) 6 0 %
(A) 15%
(B) 2 0 %
(C) 25%
(D) 4 0 %
(E) 6 0 %
Re: A pomegranate grower packages pomegranates in 10-pound and 20-pound b
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17 Jun 2023, 04:00
17 Jun 2023, 04:00
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If the grower produces more than twice as many 20-pound boxes as 10-pound boxes, then more than 2/3 of the boxes will be 20-pound boxes. Therefore, less than 1/3 of the boxes will be 10-pound boxes.
Furthermore, each 20-pound box contains twice as much fruit, by weight, as does a 10-pound box. Therefore, for every pound of pomegranates packaged in 10- pound boxes, more than (2) (2) = 4 pounds will come from 20-pound boxes. This means that less than 1/1 +(2)(2)=1/5 or 20%. of the weight of the packaged pomegranates comes from 10-pound boxes. Only choice (A) is less than 20 %.
If the grower produces more than twice as many 20-pound boxes as 10-pound boxes, then more than 2/3 of the boxes will be 20-pound boxes. Therefore, less than 1/3 of the boxes will be 10-pound boxes.
Furthermore, each 20-pound box contains twice as much fruit, by weight, as does a 10-pound box. Therefore, for every pound of pomegranates packaged in 10- pound boxes, more than (2) (2) = 4 pounds will come from 20-pound boxes. This means that less than 1/1 +(2)(2)=1/5 or 20%. of the weight of the packaged pomegranates comes from 10-pound boxes. Only choice (A) is less than 20 %.
Re: A pomegranate grower packages pomegranates in 10-pound and 20-pound b
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08 Sep 2023, 08:34
08 Sep 2023, 08:34
1
x = 10 lb boxes and y = 20lb boxes
y > 2x
Since there are no stated numbers, make y = 300 and x = 100 (complying with the y > 2x rule)
If y = 300 and x = 100:
100(10) / (300(20) + 100(10)) = 1000/(6000+1000) = 1/7
1/7 is approximately 0.14 or 14%, closest to answer choice A.
y > 2x
Since there are no stated numbers, make y = 300 and x = 100 (complying with the y > 2x rule)
If y = 300 and x = 100:
100(10) / (300(20) + 100(10)) = 1000/(6000+1000) = 1/7
1/7 is approximately 0.14 or 14%, closest to answer choice A.
