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A retail store that sells only shoes and accessories found that its re
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02 Aug 2021, 13:58
02 Aug 2021, 13:58
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A retail store that sells only shoes and accessories found that its revenues last month from those two categories could be expressed in the ratio x : y, respectively. If last month’s total revenues were $4,000, what was the difference between revenues from shoes and revenues from accessories?
A. \(\frac{x}{x+y}\)
B. \(\frac{y}{x+y}\)
C. \($4,000(\frac{x}{y})
\)
D. \( $4,000(\frac{x}{x+y})
\)
E. \($4,000(\frac{x-y}{x+y})\)
A. \(\frac{x}{x+y}\)
B. \(\frac{y}{x+y}\)
C. \($4,000(\frac{x}{y})
\)
D. \( $4,000(\frac{x}{x+y})
\)
E. \($4,000(\frac{x-y}{x+y})\)
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GRE 1: Q160 V152
A retail store that sells only shoes and accessories found that its re
[#permalink]
02 Aug 2021, 16:30
02 Aug 2021, 16:30
2
revenue from shoes=x
revenue from accessories=y
If x+y=4,000, then x-y is required with answer E
\($4,000(\frac{x-y}{x+y})=(x+y)(\frac{x-y}{x+y})\)
revenue from accessories=y
If x+y=4,000, then x-y is required with answer E
\($4,000(\frac{x-y}{x+y})=(x+y)(\frac{x-y}{x+y})\)
Carcass wrote:
A retail store that sells only shoes and accessories found that its revenues last month from those two categories could be expressed in the ratio x : y, respectively. If last month’s total revenues were $4,000, what was the difference between revenues from shoes and revenues from accessories?
A. \(\frac{x}{x+y}\)
B. \(\frac{y}{x+y}\)
C. \($4,000(\frac{x}{y})
\)
D. \( $4,000(\frac{x}{x+y})
\)
E. \($4,000(\frac{x-y}{x+y})\)
A. \(\frac{x}{x+y}\)
B. \(\frac{y}{x+y}\)
C. \($4,000(\frac{x}{y})
\)
D. \( $4,000(\frac{x}{x+y})
\)
E. \($4,000(\frac{x-y}{x+y})\)
Re: A retail store that sells only shoes and accessories found that its re
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13 Aug 2021, 01:50
13 Aug 2021, 01:50
2
Let's say, Shoe revenue < Accessory Revenue.
Now, Shoe revenue + Accessory Revenue = 4000
And, Shoe Revenue/Accessory Revenue = x/y.
For solving this problem, if we move on with the traditional algebraic process, it will be tough. So, we will consider taking values.
Let's say, Shoe revenue = 1000 and Accessory revenue = 3000. This will give us x/y = 1/3. We take, x= 1, y= 3.
So, difference = 3000-1000=2000
Now let's match the answer.
Option a: 1/4 (Nah)
Option b: 3/4 (Nah)
Option c: 4000/3 (Nah)
Option d: 1000 (Nah)
Option e: 2000 Yeah
Now, Shoe revenue + Accessory Revenue = 4000
And, Shoe Revenue/Accessory Revenue = x/y.
For solving this problem, if we move on with the traditional algebraic process, it will be tough. So, we will consider taking values.
Let's say, Shoe revenue = 1000 and Accessory revenue = 3000. This will give us x/y = 1/3. We take, x= 1, y= 3.
So, difference = 3000-1000=2000
Now let's match the answer.
Option a: 1/4 (Nah)
Option b: 3/4 (Nah)
Option c: 4000/3 (Nah)
Option d: 1000 (Nah)
Option e: 2000 Yeah
