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Re: x < y [#permalink]
2
HarveyKlaus wrote:
I found this question in Barrons practise test however, I think the answer is not correct.

My solution:
Since x < y; lets consider two cases. (1) y=4, x= 2 (2) y=-2 x=-5

If we consider the positive case, quantity A is greater. however, If we consider the negative case, quantity B is greater. So the answer should be D.
But the official answer is B. Im not able to understand why!

Any comments?

Thanks!


No, the answer is not D. The answer is B.

In both of your cases, quantity B is greater.

case 1) y=4, x= 2
Quantity A: (4+2)/2 = 3
Quantity B: (4+4+2)/3 = 3 1/3
Quantity B is greater

case 2) y=-2 x=-5
Quantity A: (-2 + -5)/2 = -3.5
Quantity B: (-2 + -2 + -5)/3 = -3
Quantity B is greater

Cheers,
Brent
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Re: x < y [#permalink]
But can't y be 0?
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Re: x < y [#permalink]
1
Hi
I got the approach that Brent sir explained but when I inserted values I got D as ans..
I took x as 2 n y as 3 in that case mean of quantity a is 2.5 n quantity b is 2.6 so B is greater..but if I take x as -3 and y as -2 the mean of quantity a is -2.5 and that of quantity b is -2.6 in which case A is greater..
Please explain me is this wrong to think like this?

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Re: x < y [#permalink]
Reetika1990 wrote:
Hi
I got the approach that Brent sir explained but when I inserted values I got D as ans..
I took x as 2 n y as 3 in that case mean of quantity a is 2.5 n quantity b is 2.6 so B is greater..but if I take x as -3 and y as -2 the mean of quantity a is -2.5 and that of quantity b is -2.6 in which case A is greater..
Please explain me is this wrong to think like this?

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If x=-3 and y=-2
A= (-3-2)/2 = -2.5
B= (-3-2-2)/3= -2.3 not -2.6

Hence, B is greater
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Re: x < y [#permalink]
mellowtubmarine wrote:
But can't y be 0?

Yes, but result will be same.
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Re: x < y [#permalink]
Not sure if this is the correct method, but how I did it was this way:
Choice A is x + y / 2
Choice B is x + y +y / 2

You know that x < y. Since y is a greater value, when you calculate the mean, the average will be pushed toward the higher values because there is the additional y. From here choice B is the answer.
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Re: x < y [#permalink]
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