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Sherry supervises a crew of maintenance engineers for an off
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Updated on: 17 Jun 2020, 08:53
Updated on: 17 Jun 2020, 08:53
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Question Stats:
72% (01:24) correct
27% (01:49) wrong based on 40 sessions
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Sherry supervises a crew of maintenance engineers for an office building. If there are 5 experienced maintenance engineers and 3 apprentice engineers and the engineers are sent out on jobs in teams, which of the following must be true?
Indicate all possible values.
A. There are 10 different 3-person teams of experienced engineers she could send.
B. There are 3 different 2-person teams of apprentice engineers she could send.
C. There are 2 different 2-person teams of apprentice engineers she could send.
D. There are 10 different 2-person teams of experienced engineers she could send.
E. There are 10 different 4-person teams of experienced engineers she could send.
Indicate all possible values.
A. There are 10 different 3-person teams of experienced engineers she could send.
B. There are 3 different 2-person teams of apprentice engineers she could send.
C. There are 2 different 2-person teams of apprentice engineers she could send.
D. There are 10 different 2-person teams of experienced engineers she could send.
E. There are 10 different 4-person teams of experienced engineers she could send.
Drill 2
Question: 11
Page: 564-565
Question: 11
Page: 564-565
Re: Sherry supervises a crew of maintenance engineers for an off
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12 Jan 2018, 15:33
12 Jan 2018, 15:33
Expert Reply
Explanation
Starting with choice (A), there are 3 slots on the team, with 5 experienced engineers available for the first slot, 4 for the second slot, and 3 for the third slot. Order doesn’t matter, so divide by 3! to get \(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\). Choice (A) is correct.
For choice (B), you have 3 apprentice engineers available for 2 slots and once again, order doesn’t matter. \(\frac{3 \times 2}{2 \times 1}= 3\). Choice (B) is correct and you can eliminate choice (C), which contradicts choice (B).
For choice (D) you have \(\frac{5 \times 4}{1 \times 2}= 10\), so choice (D) is correct.
Choice (E) is incorrect because \(\frac{5 \times 4 \times 3 \times 2}{4 \times 3 \times 2 \times 1}= 5\). The correct answers are choices (A), (B), and (D).
Starting with choice (A), there are 3 slots on the team, with 5 experienced engineers available for the first slot, 4 for the second slot, and 3 for the third slot. Order doesn’t matter, so divide by 3! to get \(\frac{5 \times 4 \times 3}{3 \times 2 \times 1}= 10\). Choice (A) is correct.
For choice (B), you have 3 apprentice engineers available for 2 slots and once again, order doesn’t matter. \(\frac{3 \times 2}{2 \times 1}= 3\). Choice (B) is correct and you can eliminate choice (C), which contradicts choice (B).
For choice (D) you have \(\frac{5 \times 4}{1 \times 2}= 10\), so choice (D) is correct.
Choice (E) is incorrect because \(\frac{5 \times 4 \times 3 \times 2}{4 \times 3 \times 2 \times 1}= 5\). The correct answers are choices (A), (B), and (D).
Re: Sherry supervises a crew of maintenance engineers for an off
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17 Jun 2020, 05:49
17 Jun 2020, 05:49
I have a mini question here:
in B, when we do the math we get three after applying combination formula.
In C, the answer is also 3, which is less than two. So, having two different teams is embedded in 3 ? Could we think that or it is totally wrong?
in B, when we do the math we get three after applying combination formula.
In C, the answer is also 3, which is less than two. So, having two different teams is embedded in 3 ? Could we think that or it is totally wrong?
