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Anne pays 150 percent more for a wholesale widget than Bart Pays, Ann
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15 Sep 2023, 02:52
15 Sep 2023, 02:52
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55% (01:55) correct
45% (01:47) wrong based on 20 sessions
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Anne pays 150 percent more for a wholesale widget than Bart Pays,
Anne's retail price per widget is 15 percent greater than the wholesale price she paid.
Bart's retail price per widget is 185 percent greater than the wholesale price he paid.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Anne's retail price per widget is 15 percent greater than the wholesale price she paid.
Bart's retail price per widget is 185 percent greater than the wholesale price he paid.
Quantity A |
Quantity B |
Anne's retail price |
Bart's retail price |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Anne pays 150 percent more for a wholesale widget than Bart Pays, Ann
[#permalink]
22 Sep 2023, 09:22
22 Sep 2023, 09:22
1
Anne pays 150 percent more for a wholesale widget than Bart Pays
=> \(A_w\) = \(B_w\) + \(\frac{150}{100}\)*\(B_w\) = 2.5 \(B_w\)
Anne's retail price per widget is 15 percent greater than the wholesale price she paid.
=> \(A_r\) = \(A_w\) + \(\frac{15}{100}\)*\(A_w\) = 1.15 \(A_w\) = 1.15 * 2.5 \(B_w\) = 2.85 * \(B_w\)
Bart's retail price per widget is 185 percent greater than the wholesale price he paid.
=> \(B_r\) = \(B_w\) + \(\frac{185}{100}\)*\(B_w\) = 2.85 \(B_w\)
Clearly, Quantity A ( \(A_r\) (=2.85 * \(B_w\))) > Quantity B (\(B_r\)(=2.85 \(B_w\)))
So, Answer will be A
Hope it helps!
=> \(A_w\) = \(B_w\) + \(\frac{150}{100}\)*\(B_w\) = 2.5 \(B_w\)
Anne's retail price per widget is 15 percent greater than the wholesale price she paid.
=> \(A_r\) = \(A_w\) + \(\frac{15}{100}\)*\(A_w\) = 1.15 \(A_w\) = 1.15 * 2.5 \(B_w\) = 2.85 * \(B_w\)
Bart's retail price per widget is 185 percent greater than the wholesale price he paid.
=> \(B_r\) = \(B_w\) + \(\frac{185}{100}\)*\(B_w\) = 2.85 \(B_w\)
Clearly, Quantity A ( \(A_r\) (=2.85 * \(B_w\))) > Quantity B (\(B_r\)(=2.85 \(B_w\)))
So, Answer will be A
Hope it helps!
General Discussion
Re: Anne pays 150 percent more for a wholesale widget than Bart Pays, Ann
[#permalink]
22 Sep 2023, 08:05
22 Sep 2023, 08:05
1
A little confused on why the answer choice is A.
If Bart paid 100, then Anne pays 150.
Anne's retail price is 150 * 1.15 = 172.5
Bart's retail price is 100 * 1.85 = 185.
185 > 172.5, so shouldn't Bart's retail price be greater?
If Bart paid 100, then Anne pays 150.
Anne's retail price is 150 * 1.15 = 172.5
Bart's retail price is 100 * 1.85 = 185.
185 > 172.5, so shouldn't Bart's retail price be greater?
