GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dave bought a few pencils and a few erasers. Each pencil costs 12 cent
[#permalink]
16 Oct 2023, 09:34
16 Oct 2023, 09:34
Expert Reply
1
Bookmarks
00:00
Question Stats:
100% (03:06) correct
0% (00:00) wrong based on 5 sessions
Hide Show timer Statistics
Dave bought a few pencils and a few erasers. Each pencil costs 12 cents and each eraser costs 20 cents. He bought at least one of both the items and spent a total of 108 cents.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Number of pencils |
Number of erasers |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Part of the project: The Butler-GRE Daily New Quant and Verbal Questions to Practice (2023) - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Manager
Joined: 11 Nov 2023
Posts: 211
Given Kudos: 76
WE:Business Development (Advertising and PR)
Dave bought a few pencils and a few erasers. Each pencil costs 12 cent
[#permalink]
04 Dec 2023, 23:13
04 Dec 2023, 23:13
1
Right off the bat, we know that the numbers of pencils and erasers must be integers greater than or equal to 1.
Interpret into an equation, where x = number of pencils and y = number of erasers:
\(12x + 20y = 108\)
We can see that x must be a multiple of 4, because it's the only way that \(y=\frac{108-12x}{20}\) would also be an integer (i.e., have a remainder of 0).
Let's try \(x=4\):
\(12(4)+20y=108\)
\(20y=60\)
\(y=3\)
4>3, so A>B.
Interpret into an equation, where x = number of pencils and y = number of erasers:
\(12x + 20y = 108\)
We can see that x must be a multiple of 4, because it's the only way that \(y=\frac{108-12x}{20}\) would also be an integer (i.e., have a remainder of 0).
Let's try \(x=4\):
\(12(4)+20y=108\)
\(20y=60\)
\(y=3\)
4>3, so A>B.
gmatclubot
Dave bought a few pencils and a few erasers. Each pencil costs 12 cent [#permalink]
04 Dec 2023, 23:13
Moderators:
