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On an excursion trip of 5 hours, Mary averaged p miles per hour for 2
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17 Oct 2023, 23:53
17 Oct 2023, 23:53
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On an excursion trip of 5 hours, Mary averaged p miles per hour for 2 hours and q miles per hour for the rest of the journey. It is known that \(p +\frac{3}{2}q = 140.\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Mary’s average speed for the entire trip |
56 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
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Re: On an excursion trip of 5 hours, Mary averaged p miles per hour for 2
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04 Dec 2023, 22:38
04 Dec 2023, 22:38
1
Distance = Time x Rate, or Rate = Distance / Time. We're given Time, and the Distance in terms of p and q.
Since we know total time was 5 hours, Mary traveled for 3 hours at the rate of q. So, we can interpret the first part as:
\(2p+3q =D\), where D is total distance traveled.
We're also given \(p+\frac{3}{2}q=140\)
Multiply both sides by 2:
\(2(p+\frac{3}{2}q)=2*140\)
\(2p+3q=280=D\)
However, we want to find the Rate:
\(= D/5 = 280/5 = 56\)
Since we know total time was 5 hours, Mary traveled for 3 hours at the rate of q. So, we can interpret the first part as:
\(2p+3q =D\), where D is total distance traveled.
We're also given \(p+\frac{3}{2}q=140\)
Multiply both sides by 2:
\(2(p+\frac{3}{2}q)=2*140\)
\(2p+3q=280=D\)
However, we want to find the Rate:
\(= D/5 = 280/5 = 56\)
gmatclubot
Re: On an excursion trip of 5 hours, Mary averaged p miles per hour for 2 [#permalink]
04 Dec 2023, 22:38
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