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If A, B, C, D, and E are points in a plane such that line CD
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30 Sep 2018, 02:39
30 Sep 2018, 02:39
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Question Stats:
62% (01:31) correct
37% (01:49) wrong based on 74 sessions
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If A, B, C, D, and E are points in a plane such that line CD bisects ∠ACB and line CB bisects right angle ∠ACE, then ∠DCE =
(A) 22.5°
(B) 45°
(C) 57.5°
(D) 67.5°
(E) 72.5°
(A) 22.5°
(B) 45°
(C) 57.5°
(D) 67.5°
(E) 72.5°
Re: If A, B, C, D, and E are points in a plane such that line CD
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01 Oct 2018, 04:05
01 Oct 2018, 04:05
explain pls??
Re: If A, B, C, D, and E are points in a plane such that line CD
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01 Oct 2018, 07:50
01 Oct 2018, 07:50
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OE
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Quote:
CD bisects ∠ ACB
CB bisects ∠ ACE
We are given that CB bisects the right-angle ∠ ACE. Hence, ∠ ACB = ∠ BCE = ∠ ACE/2 = 90°/2 = 45°. Also, since CD bisects ∠ ACB, ∠ ACD = ∠ D C B = ∠ ACB/2 = 45°/2 = 22.5°. Now, ∠ DCE =
∠ DCB + ∠ BCE = 22.5° + 45° = 67.5°. The answer is (D).
CB bisects ∠ ACE
We are given that CB bisects the right-angle ∠ ACE. Hence, ∠ ACB = ∠ BCE = ∠ ACE/2 = 90°/2 = 45°. Also, since CD bisects ∠ ACB, ∠ ACD = ∠ D C B = ∠ ACB/2 = 45°/2 = 22.5°. Now, ∠ DCE =
∠ DCB + ∠ BCE = 22.5° + 45° = 67.5°. The answer is (D).
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