motion2020 wrote:
Total number of classes = 2*32=64
37 teachers taught 64 classess implies that at least 37 classes had 1 teacher, and the remaining 27 classes had 2 or 3 teachers. For any teacher to teach 3 classes, the teacher must sign on to 2 additional classes. Hence, \(27/2\) results in 13
Quantity A: 13
Quantity B: 13
answer is
C KarunMendiratta wrote:
A Mathematics program was tried out in 2 classes in each of 32 elementary schools which involved 37 teachers. Each of the classes had 1 teacher and each of the teachers taught at least 1, but not more than 3 classes.
Quantity A |
Quantity B |
Greatest number of teachers who taught 3 classes |
13 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Carcass, why is he dividing by 2? Is there an alternative way of solving this?
Even I got that 27 classes have teachers who are either teaching 2 classes or 3 classes. So, to maximise teachers teaching 3 classes, we will have to consider that no one is teaching 2 classes, then all 27 teach 3 classes? But this doesn't make too much sense. Please help!!