sandy wrote:
\((x^2)(y) < 0\)
Quantity A: xy
Quantity B: 0
Since x^2 is always greater than or equal to zero, and since x^2 does not equal zero (since we're told the expression (x^2)(y) is LESS THAN 0), we can be certain that x^2 is POSITIVE and y is NEGATIVE.
Of course, that x^2 is POSITIVE tells us nothing about whether x itself is positive or negative.
So, x could be positive, or x could be negative.
This brings us to two conflicting cases:
case 1: x = 1 and y = -1
Aside: notice that this satisfies the given inequality (x^2)(y) < 0
In this case we get:
Quantity A: xy = (1)(-1) = -1
Quantity B: 0
Here,
quantity B is greater.
case 2: x = -1 and y = -1
Aside: notice that this satisfies the given inequality (x^2)(y) < 0
In this case we get:
Quantity A: xy = (-1)(-1) = 1
Quantity B: 0
Here,
quantity A is greater.
Since we can't conclude which quantity is greater, the correct answer is
Cheers,
Brent