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x and y are positive integers such that 2^x+2y = 8.
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30 Nov 2023, 23:48
30 Nov 2023, 23:48
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49% (01:29) wrong based on 14 sessions
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x and y are positive integers such that \(2^{x+2y} = 8\).
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
xy |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
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x and y are positive integers such that 2^x+2y = 8.
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01 Dec 2023, 19:18
01 Dec 2023, 19:18
1
\(8 = 2^3\)
So we can rewrite the equation as
\(2^{x+2y}=2^3\)
Bring the exponents down,
\(x+2y = 3\)
We're told that x and y are positive integers, so the only value of x and y that would satisfy the equation is 1.
Plug the 1 into xy, and we get 1.
Thus, columns A and B are equal.
So we can rewrite the equation as
\(2^{x+2y}=2^3\)
Bring the exponents down,
\(x+2y = 3\)
We're told that x and y are positive integers, so the only value of x and y that would satisfy the equation is 1.
Plug the 1 into xy, and we get 1.
Thus, columns A and B are equal.
x and y are positive integers such that 2^x+2y = 8.
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29 Jan 2024, 07:51
29 Jan 2024, 07:51
1
We solve the equation \(2^{x+2y} = 8\) by equalizing the bases
\(2^{x+2y} = 2^3\)
We can now equate the exponents
\(x+2y = 3\)
Since we know that \(x\) and \(y\) are both positive integers, the only way \(x+2y = 3\) can be true is if
\(x=y=1\)
Quantity A
\(xy = 1\)
Quantity B
\(1\)
BOTH quantities are EQUAL.
The answer is C.
\(2^{x+2y} = 2^3\)
We can now equate the exponents
\(x+2y = 3\)
Since we know that \(x\) and \(y\) are both positive integers, the only way \(x+2y = 3\) can be true is if
\(x=y=1\)
Quantity A
\(xy = 1\)
Quantity B
\(1\)
BOTH quantities are EQUAL.
The answer is C.
